71 MPM (Meters Per Minute)
S = Speed
D = Distance
T = Time
to find the Speed you divide D by your T
The acceleration of the bus is 1.11 meters per second square to the direction of motion
Explanation:
Acceleration is the rate of change of velocity
The formula of the acceleration is , where
- is the initial velocity
- is the final velocity
- t is the time
A bus that goes from 10 km/h to a speed of 50 km/h in 10 seconds
→ = 10 km/h
→ = 50 km/h
→ t = 10 seconds
Change the unite of the time from seconds to hour
→ 1 hour = 60 × 60 = 3600 seconds
→ 10 seconds = hour
Substitute these values in the formula of the acceleration above
→
→ a = 14400 km/h²
To change the unit of acceleration to meter per second change the
kilometer to meter and the hour to seconds
→ 1 km = 1000 m
→ 1 hour = 3600 seconds
→
→ a = 1.11 m/sec².
The acceleration of the bus is 1.11 meters per second square to the direction of motion
Learn more:
You can learn more about the acceleration in brainly.com/question/6323625
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Answer:
Option A
Explanation:
At segment T-U, the substance changes from a liquid to a gas and does not change temperature.
The reason is because latent heat of vaporisation allows for the absorption of heat in the change of state and temperature remains constant until it has fully changed state.
Answer:
1.63366
Explanation:
I got this answer from calculator soups physics calculators. I really recommend their website for formulas.
Answer:
A u = 0.36c B u = 0.961c
Explanation:
In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains
u ’= (u-v) / (1- uv / c²)
Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory
The data give is u ’= 0.43c and the initial core velocity v = 0.94c
Let's clear the speed with respect to the observer (u)
u’ (1- u v / c²) = u -v
u + u ’uv / c² = v - u’
u (1 + u ’v / c²) = v - u’
u = (v-u ’) / (1+ u’ v / c²)
Let's calculate
u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)
u = 0.51c / (1 + 0.4042)
u = 0.36c
We repeat the calculation for the other piece
In this case u ’= - 0.35c
We calculate
u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)
u = 1.29c / (1- 0.329)
u = 0.961c