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3 years ago

Explain how the particles of solids move

Physics

1 answer:

KiRa [710]3 years ago

3 0

Answer:

Matter in a solid state are packed tightly in place and vibrate.

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okay so there is a wheel and it shows it when its high, in the middle, and below. my question is when is its potenial energy the

earnstyle [38]

At the highest point

cheers

4 0

4 years ago

Which of the following surfaces reflects the most light

Gre4nikov [31]

Answer:

Explanation:

it could be the yellow cloth but we see are shadow on the sidewalk most of the time and shadows are made from reflecting light so your answer should be D

3 0

3 years ago

Read 2 more answers

the physics concept corresponding to oomph is momentum. building on your above answers, figure out a formula for momentum (oomph

topjm [15]

Momentum = mass * velocity

I need parts A and B to explain the intuitions.

7 0

3 years ago

You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. Both strike the wall at speed v, but while the

lana [24]

Answer:

<em>The fifth option is the correct answer: mv; 2 mv</em>

Explanation:

<u>Change of Momentum</u>

Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is

$\Delta p=p_2-p_1$

The momentum is computed as

$p=mv$

Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.

The clay has an initial speed v and a mass m, thus its initial momentum is

$p_1=mv$

When it hits the wall, it sticks, thus its final speed is 0 and

$p_2=0$

The change of momentum is

$\Delta p=0-mv=-mv$

The absolute change is mv

Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is

$p_2=-mv$

The change of momentum is

$\Delta p=-mv-mv=-2mv$

The absolute change is 2mv

The fifth option is the correct answer: mv; 2 mv

3 0

4 years ago

A 1000-kilogram car traveling due east at 15 meters per second hit from behind and receives a forward impulse of 6000 newton-sec

strojnjashka [21]

The change in momentum of the car is 6000 kg m/s

Explanation:

According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on the object, therefore:

$\Delta p = I$

where

$\Delta p$ is the change in momentum

I is the impulse exerted

For the car in this problem, the impulse received is

I = 6000 kg m/s (in the forward direction)

Therefore, the change in momentum of the car is equal to this value:

$\Delta p = I = 6000 kg m/s$ (in the forward direction)

We can also calculate what is the new momentum of the car. In fact, the initial momentum is

$p_i = mu = (1000 kg)(15 m/s)=15,000 kg m/s$

And so, the new momentum is

$p_f = p_i + \Delta p = 15,000 + 6,000 = 21,000 kg m/s$

Learn more about impulse and momentum:

brainly.com/question/9484203

#LearnwithBrainly

8 0

3 years ago