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3 years ago

Samples of different materials, A and B, have the same mass, but the sample

Physics

1 answer:

Lynna [10]3 years ago

4 0

Explanation:

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The universe is filled with photons left over from the Big Bang that today have an average energy of about 4.9 ✕10-4 (correspond

motikmotik

Answer:

The number of available energy is $4.820\times10^{45}$

Explanation:

Given that,

Energy $E=4.9\times10^{-4}\ J$

Temperature = 2.7 K

Energy states per unit volume $dE=4\times10^{-5}\ eV$

We need to calculate the number of available energy

Using formula of energy

$N=g(E)dE$

$N=\dfrac{8\pi\times E^2 dE}{(hc)^3}$

Where, h = Planck constant

c = speed of light

E = energy

Put the value into the formula

$N=\dfrac{8\pi\times(4.9\times10^{-4})^2\times4\times10^{-5}\times1.6\times10^{-19}}{(6.67\times10^{-34}\times3\times10^{8})^3}$

$N=4.820\times10^{45}$

Hence, The number of available energy is $4.820\times10^{45}$

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3 years ago

If a fertilized egg cannot reach the uterus, what is the most likely result?

murzikaleks [220]

D. A fetus will develop in the fallopian tube.

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3 years ago

Read 2 more answers

Which physical property is used to identify matter based on solubility

Pani-rosa [81]

Volume is the answer.

8 0

3 years ago

You travel an an average speed of 20 km/h in a straight line to get to your grandmothers house. It takes you 3 hours to get to h

Ber [7]

20km every 1 hr is what 20km/hr means.

so 3hrs is 20km*3=60km.

6 0

4 years ago

Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with

Anni [7]

Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg v_a = 2.2 m/s

m_b = 1.6 kg v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

= 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

V₃ₓ = 32.44 m/s (toward right)

by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

$v = \sqrt{32.44^2 + (-1.8)^2}$

v = 32.49 m/s

$tan \theta = \dfrac{-1.8}{32.44}$

$\theta = tan^{-1}(\dfrac{-1.8}{32.44})$

θ = 3.176° (downward with horizontal)

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3 years ago