Answer:

Step-by-step explanation:
In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.
Evaluating the integral gives use that it is equal to;

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.
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Answer:
y=ax+b
a=-0.6020457867
b=-2.256697516 <------- There is your value for b, which is the answer to the problem.
You can use these values for a and b to generate an equation in slope-intercept form, which you can then enter under Y= and view the graph.
Step-by-step explanation:
Answer:
54
Step-by-step explanation:
delta math.
yea....................
9514 1404 393
Answer:
║w║ = 6
Step-by-step explanation:
(c) The magnitude of w is computed the same way the magnitudes of the other vectors are computed. It is the root of the sum of the squares of the components.
║w║= ║<-6, 0>║ = √((-6)² +0²) = √36
║w║= 6
Answer:
what do you need?
Step-by-step explanation:
I don't see a question.