We need to solve for the height of the tree and we need to define the variable that would represent this value. In this case, we assign "y" for the unknown height of the tree. See attached picture for better comprehension.
Solving for the variable "a" which is base of downhill to the tree, we have it:
cos 20° = a / 15 ft
a = 15*cos 20°
a = 14.095 feet
Solving for the variable "x" which is the side of the hill to the base of the tree, we have it:
sin 20° = x / 15 ft
x = 15 * sin20°
x = 5.130 feet
Solving for the variable "y", which is the height of the tree, we have it:
tan 45° = (x+y) / a
tan 45° = (5.13 + y) / 14.095
y = 14.095*tan45° - 5.13
y = 8.965 feet
The height of the tree is
8.965 feet.
Answer: Answer: 14 : 12 , 21 : 18 and 28 : 24
Please brainliest i answer first
Answer:
64.65% probability of at least one injury commuting to work in the next 20 years
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Each day:
Bikes to work with probability 0.4.
If he bikes to work, 0.1 injuries per year.
Walks to work with probability 0.6.
If he walks to work, 0.02 injuries per year.
20 years.
So

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

We want
. Then

In which



64.65% probability of at least one injury commuting to work in the next 20 years
Answer:
A ≈ 12.57
Step-by-step explanation:
You have to take the formula: A = πr^2
1) Plug in what you know: A = π•2^2
2) π = 3.14 and 2^2 = 4
3) Multiply to get: 12.56637
4) Round
A ≈ 12.57
N(N ∩ S ∩ K) = 10
n(ξ) = 250
n(S ∪ K) = 15 - 10 = 5
n(N ∪ S) = 20 - 10 = 10
n(N ∪ K) = 30 - 10 = 20
n(S) = 50 - 10 - 5 - 10 = 25
n(K) = 55 - 20 - 5 - 10 = 20
n(N) = 100 - 10 - 20 - 10 = 60
n(N ∪ S ∪ K) = 10 + 5 + 10 + 20 + 25 + 20 + 60 = 150
Therefore, n(N ∪ S ∪ K)' = 250 - 150 = 100
Therefore, 100 million people do not read any of the three papers.