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Blababa [14]
3 years ago
10

P is inversely proportional to q² when q= 32 and p=16 find p when q=6

Mathematics
2 answers:
Strike441 [17]3 years ago
8 0
I think it would be p=96
RideAnS [48]3 years ago
4 0

Answer:

p is inversely proportional to q² when q= 32 and p=16 find p when q=6

q²= 1/p

32=q

p=16

find p, when q=6

p=36

Step-by-step explanation:

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Law Incorporation [45]

Answer:

133

Step-by-step explanation:

No: of figures = 3

Fig 1 = l x b = 12 x 6 = 72

Fig 2 = l x b = 13 x 5 = 45

Fig 3 = s xs = 4x 4 = 16

Fig area=  fig 1+ fig 2+fig 3 = 72+45+16 = 133

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What is the slope of the line y=3x/7 + 4/7
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Answer:

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5 0
3 years ago
What is the algebraic way to solve -10(x-17) = -3 ? Please provide the correct solution :)
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Answer:173/10

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the slope of each line and then determine if the lines are parallel, perpendicular or neither. If a value is not an integer
Aleonysh [2.5K]

As given by the question

There are given that the point of two-line

\begin{gathered} (1,\text{ 7) and (5, 5)} \\ (-1,\text{ -3) and (1, 1)} \end{gathered}

Now,

From the condition of a parallel and perpendicular line

If the slopes are equal then the lines are parallel

If the slopes are negative reciprocal then the lines are perpendicular

If the slopes are neither of the above are true then lines are neither

Then,

First, find the slope of both of line

So,

For first-line, from the formula of slope

\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{5_{}-7_{}}{5_{}-1_{}} \\ m_1=-\frac{2}{4} \\ m_1=-\frac{1}{2} \end{gathered}

Now,

For second-line,

\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{1_{}-(-3)_{}}{1-(-1)_{}} \\ m_1=\frac{4}{2} \\ m_1=2 \end{gathered}

The given result of the slope is negative reciprocal because

\begin{gathered} -\frac{1}{2}=-(-\frac{2}{1}) \\ -\frac{1}{2}=2 \end{gathered}

Hence, the slope of line1 is -1/2, and slope of line2 is 2 and the lines are perpendicular.

5 0
1 year ago
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