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iVinArrow [24]
4 years ago
8

Given the unbalanced reaction, Fe + S​ ​---​-> Fe​ S​ , how 8​ 2​ 3​

Chemistry
1 answer:
e-lub [12.9K]4 years ago
5 0

Answer:

The answer to your question is 3 moles of Fe and 4.5 moles of S

Explanation:

Data

moles of Fe = ?

moles of S = ?

moles of Fe₂S₃

Unbalanced chemical reaction

                    Fe   +  S   ⇒    Fe₂S₃

             Reactants    Elements    Products

                     1                  Fe                2

                     1                   S                 3

Balanced chemical reaction

                    2Fe   +  3S   ⇒    Fe₂S₃

             Reactants    Elements    Products

                     2                  Fe                2

                     3                   S                 3

-Calculate the moles of each reactant

                  2 moles of Fe ------------------- 1 mol of Fe₂S₃

                 x                       -------------------- 1.5 moles Fe₂S₃

                               x = (1.5 x 2) / 1

                                x = 3 moles of Fe

-Calculate the moles of S

                  3 moles of S --------------------- 1 mol of Fe₂S₃

                  x                    --------------------- 1.5 moles of Fe₂S₃

                                x = (1.5 x 3) / 1

                                x = 4.5 moles of S

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Montano1993 [528]
Chemical reaction: SO₄²⁻ + Ba²⁺ → BaSO₄.
m(sample) = 1,543 g.
m(BaSO₄) = 0,2243 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,2243 g ÷ 233,4 g/mol. 
n(BaSO₄) = 0,00096 mol.
n(BaSO₄) = n(SO₄²⁻).
ω(SO₄²⁻) = m(SO₄²⁻) ÷ m(sample).
ω(SO₄²⁻) = 0,00096 mol · 96 g/mol ÷ 1,543 g.
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What energy is based on height?
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Potential Energy

Explanation:

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3 years ago
At what time will the pressure of SO₂Cl₂ decline to 0.50 its initial value? Express your answer using two significant figures.
QveST [7]

Answer: The time is 0.69/k seconds

Explanation:

The following integrated first order rate law

ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t

where

[SO₂Cl₂] concentration at time t,

[SO₂Cl₂]₀ initial concentration,

k rate constant

Therefore, the time elapsed after a certain concentration variation is given by:

t=\frac{ln[SO_{2}Cl_{2}]_{0} - ln[SO_{2}Cl_{2}]}{k}=\frac{ln\frac{[SO_{2}Cl_{2}]_{0}}{[SO_{2}Cl_{2}]} }{k}

We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:

p_{(SO_{2}Cl_{2})}V = n_{(SO_{2}Cl_{2})}RT

[SO_{2}Cl_{2}]= \frac{n_{(SO_{2}Cl_{2})}}{V}}=\frac{p_{(SO_{2}Cl_{2})}}{RT}}

In conclusion,

t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{p_{(SO_{2}Cl_{2})}} }{k}

for

p_{(SO_{2}Cl_{2})}=0.5p_{(SO_{2}Cl_{2})}_{0}

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{0.5p_{(SO_{2}Cl_{2})_{0}}} }{k}

t=\frac{ln\frac{1}{0.5} }{k}

t=\frac{ln(2)}{k}

t=\frac{0.69}{k}}

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Explanation:

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belka [17]

It will occupy 18 L volume when the pressure is changed to 0. 5 atm and the temperature remain constant.

Calculation,

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P_{2} V _{2} = k    (ii)

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Boyle law used during respiration or breathing.

To Learn more about Boyle law

brainly.com/question/1437490

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