Given: Altitude of satellite r = 13,300 Km convert to meter
r = 1.33 x 10⁷ m
Universal Gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²
Mass of the earth Me = 5.98 x 10²⁴ Kg
Required: Period of satellite T = ?
Formula: F = ma; Centripetal acceleration ac = V²/r F = GMeMsat/r²
Velocity of satellite V = 2πr/T
equate T from all given equation.
F = ma
GMeMsat/r² = MsatV²/r cancel Msat and insert V = 2πr/T
GMe/r² = (2πr)²/rT² Equate T or period of satellite
T² = 4π²r³/GMe
T² = 39.48(1.33 X 10⁷ m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)
T² = 9.29 x 10²² m³/3.99 x 10¹⁴ m³/s²
T² = 232,832,080.2 s²
T = 15,258.84 seconds or (it can be said around 4.24 Hr)
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Answer:
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Explanation:
The formula to be used here is
Q = It
where Q is the quantity of electricity and it is measured coulombs (C); 2.8 × 10⁻⁸ C or 0.000000028 C
I is current and it is measured in ampere (amps or A); unknown
t is time and it is measured in seconds (s); 0.05 s
Since, average current is what is unknown
I =Q/t
I = 0.000000028/0.05
I = 5.6 × 10⁻⁷ A
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Speed = 8000m/20min = 400m/min
Convert meters/min to meters/second.
60seconds in 1minute:
400m/60sec = 6.67m/s
Speed is: 6.67m/s
