From the geometry of the problem, the 20 m-long cable creates
the hypotenuse of a right triangle, with the extended of the other two sides of
size 20 m * cos(30 deg), which is around 17.3 m. Therefore, the ball has increased
by 20 m - 17.3 m = 2.7 m.
The potential energy will have altered by m*g*h, which is 1400 kg * 9.8 m/s^2 *
1.6 m , or about 37044 joules.
La longitud <em>final</em> del puente de acero es 100.018 metros.
Asumamos que la dilatación <em>térmica</em> experimentada por el puente de acero es <em>pequeña</em>, de modo que podemos emplear la siguiente aproximación <em>lineal</em> para determinar la longitud <em>final</em> del puente de acero (
), en metros:
(1)
Donde:
- Longitud inicial del puente, en metros.
- Coeficiente de dilatación, sin unidad.
- Temperatura inicial, en grados Celsius.
- Temperatura final, en grados Celsius.
Si tenemos que
,
,
y
, entonces la longitud final del puente de acero es:
![L = (100\,m)\cdot [1+(11.5\times 10^{-6})\cdot (24\,^{\circ}C - 8\,^{\circ}C)]](https://tex.z-dn.net/?f=L%20%3D%20%28100%5C%2Cm%29%5Ccdot%20%5B1%2B%2811.5%5Ctimes%2010%5E%7B-6%7D%29%5Ccdot%20%2824%5C%2C%5E%7B%5Ccirc%7DC%20-%208%5C%2C%5E%7B%5Ccirc%7DC%29%5D)

La longitud <em>final</em> del puente de acero es 100.018 metros.
Para aprender más sobre dilatación térmica, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/24953416
Answer:
F=1.65 x 10²⁶ N
Explanation:
Given that
Distance ,R= 3.34 x 10¹² m
Mass m₁= 2.78 x 10³⁰ kg
Mass ,m₂= 9.94 x 10³⁰ kg
we know that gravitational force F given as

G=Constant
G=6.67 x 10⁻¹¹ Nm²/kg²
Now by putting the values

F=1.65 x 10²⁶ N
Therefore the force between these two mass will be 1.65 x 10²⁶ N.
Answer:
Explanation:
Component of force F₁ in right direction = F₁cos37
= 12 x cos37 = 9.58 N .
Component of force F₂ in vertically upward direction = F₁sin37
= 12 x sin37 = 7.22 N .
a ) Let normal force be R
R + F₁sin37 = mg
R + 7.22 = 1.5 x 9.8 = 14.7
R = 7.48 N .
b )
Net force in horizontal direction = F₂ - F₁cos37
= F₂ - 9.58
This is equal to zero as body is moving with zero acceleration
F₂ - 9.58 = 0
F₂ = 9.58 N
c ) If body is moving with acceleration of 2.5 m /s² along the direction of F₂
F₂ - 9.58 = 1.5 x 2.5 = 3.75
F₂ = 13.33 N .