Answer:
0.364 L
Explanation:
Para resolver este problema es necesario <em>expresar la densidad en g/L</em>.
Para hacer esa conversión primero <u>convertimos m³ en L</u>:
- 1100
= 1.1 kg/L
Y después<u> convertimos kg en g</u>:
- 1.1 kg/L *
= 1100 g/L
Finalmente d<em>ividimos la masa deseada</em> (400 g) <em>entre la densidad</em>, para <u>calcular el volumen</u>:
- 400 g ÷ 1100 g/L = 0.364 L
Answer:
b. the rate of destruction is equal to the rate of carbonate input.
Explanation:
At the Calcite Compensation Depth(CCD) the rate of addition of calcite and dissolution of the mineral is the same. Below this depth, all calcite minerals are dissolved.
The CCD occurs at a depth of 3000-4000m. It varies from places to places within the ocean. Other factors play important roles in determining the CCD. Some of the factors are temperature and pressure.
Density of a liquid determines how it will layer (heaviest to lightest). If the liquid is least dense it will float to the bottom. Layers will remain separated because each liquid is actually floating on top of the more dense liquid beneath it.
Before addition of HCl,
conc. of CH3COOH = 0.450 M
conc. of CH3COONa = 0.550 M
After addition of 0.08 M HCl, following reaction occurs in system:
HCl + CH3COONa ↔ CH3COOH + NaCl
Thus, in reaction system conc. of CH3COOH will increase to 0.53 M (0.08M + 0.450M)
And, conc to CH3COONa will reduce to 0.47 M (0.550M - 0.08M)
Now, conc. of H+ ions = ka
![\frac{[acid]}{[conjugated base]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Bacid%5D%7D%7B%5Bconjugated%20base%5D%7D)
where ka = dissociation constant for acid = 10^-5 for Ch3COOH
∴ conc. of H+ ions =
= 1.1277 x 10^-5
Now, pH = -log [H+] = -log (1.1227 x 10^-5) = 4.94
