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Mars2501 [29]
3 years ago
13

Hydrogen gas can be produced by reacting aluminum with sulfuric acid. how many moles of sulfuric acid are needed to completely r

eact with 15.0 mol of aluminum? 2al(s) + 3h2so4(aq) ® al2(so4)3(aq) + 3h2(g)
Chemistry
2 answers:
g100num [7]3 years ago
8 0
The balanced equation for the reaction is as follows
2Al + 3H₂SO₄ --> Al₂(SO₄)₃ + 3H₂
stoichiometry of Al to H₂SO₄ is 2:3
number of Al moles reacted - 15.0 mol 
if 2 mol of Al react with 3 mol of H₂SO₄
then 15.0 mol of Al reacts with - 3/2 x 15.0 mol = 22.5 mol 
22.5 mol of H₂SO₄ is required 
Damm [24]3 years ago
7 0

Answer : The number of moles of sulfuric acid needed are, 22.5 moles

Explanation : Given,

Moles of aluminium = 15 moles

The given balanced chemical reaction is,

2Al(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2(g)

By the stoichiometry we can say that, 2 moles of aluminium react with 3 moles of sulfuric acid to give 1 mole of aluminium sulfate and 3 moles of hydrogen gas.

From the balanced chemical reaction, we conclude that

As, 2 moles of aluminium react with 3 moles of sulfuric acid

So, 15 moles of aluminium react with \frac{3}{2}\times 15=22.5 moles of sulfuric acid

Therefore, the number of moles of sulfuric acid needed are, 22.5 moles

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7.86 is the pOH of water at this temperature of 100 degrees celsius.

Option E is the right answer.

Explanation:

Data given:

Kw = 51.3 x 10^{-14}

pOH = ?

we know that pure water is neutral and will have pH pf 7.

The equation for relation between Kw and H+ and OH- ion is given by:

Kw = [H+] [OH-}

here the concentration of H+ ion and OH- ion is equal

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Putting the values in the equation of Kw

pKw = -log[Kw]

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8 0
3 years ago
As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is
chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

<em>KBrO₃ → K⁺ + BrO₃⁻ </em>

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = <em>38,0 kJ/mol</em>

<em></em>

I hope it helps!

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