Answer: Polar air mass is the large mass of air formed over land or water in higher latitudes. They are characterized by cold air.
Tropical air mass is the large mass of air that is formed 25 degrees latitude of the equator. They are characterized by warm air.
Explanation:
Polar air mass is known for cold air near earth's surface. Polar air mass takes place in cold regions like Arctic region.
Unlike tropical air mass, polar air mass brings cold and dry air weather in winter season.
Continental polar mass takes place in cold, stable and low humid areas like subpolar land. Whereas, maritime polar air mass forms over oceans which are cool and located in polar region.
Tropical air mass is characterized by warm to hot air. But, as this air mass move away from their latitude of origin, they get cooled down. This phenomenon mostly result in precipitation and storms in Unites States. This also shows that tropical air mass contains moisture. They are usually prone to sudden changes.
Continental tropical air mass is produced over desert areas of the world during summer, when its hot. While, maritime tropical air mass is produced over tropical and subtropical oceans and seas in the world.
3 CuSO4(aq)+2Al(s) -->Al2(SO4)3(aq)+Cu(s) is a
balanced equation for Copper (II) sulfate + aluminum --> aluminum
sulfate+solid copper. The correct answer between all the choices
given is the second choice or letter B. I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
Given data:
Hydrogen (H) = 3.730 % by mass
Carbon (C) = 44.44%
Nitrogen (N) = 51.83 %
This means that if the sample weighs 100 g then:
Mass of H = 3.730 g
Mass of C = 44.44 g
Mass of N = 51.83 g
Now, calculate the # moles of each element:
# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles
# moles of C = 44.44/12 = 3.703 moles
# moles of N = 51.83/14 = 3.702 moles
Divide by the lowest # moles:
H = 3.730/3.702 = 1
C = 3.703/3.702 = 1
N = 3.702/3.702 = 1
Empirical Formula = HCN
Answer : The standard cell potential of the reaction is, -1.46 V
Explanation :
The given balanced cell reaction is,
Here, chromium (Cr) undergoes oxidation by loss of electrons and act as an anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.
The standard values of cell potentials are:
Standard reduction potential of lead ![E^0_{[Pb^{2+}/Pb]}=-0.13V](https://tex.z-dn.net/?f=E%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D%3D-0.13V)
Standard reduction potential of chromium ![E^0_{[Cr^{3+}/Cr]}=1.33V](https://tex.z-dn.net/?f=E%5E0_%7B%5BCr%5E%7B3%2B%7D%2FCr%5D%7D%3D1.33V)
Now we have to calculate the standard cell potential for the following reaction.
![E^0=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cr^{3+}/Cr]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D-E%5E0_%7B%5BCr%5E%7B3%2B%7D%2FCr%5D%7D)
Therefore, the standard cell potential of the reaction is, -1.46 V
When we look at the periodic table, it tells us the Sodium is labeled as 'Na'.
