Question

Complete this equation for the dissociation of na2co3(aq). omit water from the equation because it is understood to be present.

Answer 1

Note that we are omitting the water.

So, sodium carbonate will basically dissociate into positive sodium ions and negative carbonate ions based on the following equation:
 Na2CO3 → 2 Na(+) + CO3(2-)

If we took water into consideration:
Sodium carbonate will dissociate in water forming carbonic acid and sodium hydroxide. Since sodium hydroxide is a strong base, therefore, it will then neutralize the gastric acid, thus, acting as an antacid.

Answer 2

The equation for the dissociation of ${\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_3}$ is $\boxed{{\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_3}\to2{\text{N}}{{\text{a}}^ + }+{\text{CO}}_3^{2 - }}$

Further Explanation:

The attraction between atoms, molecules or ions which results in the formation of chemical compounds is known as a chemical bond. It is formed either due to electrostatic forces or by the sharing of electrons. There are many strong bonds such as ionic bonds, covalent bonds, and metallic bonds while some weak bonds like dipole-dipole interactions, London dispersion forces, and hydrogen bonding.

Ionic compounds are the compounds that are formed from the ions of the respective species. Ions are the species that are formed either due to loss or gain of electrons. A neutral atom forms cation by the loss of electrons and anion by the gain of electrons.

For example, ${\text{MgC}}{{\text{l}}_2}$ is an ionic compound formed from one ${\text{M}}{{\text{g}}^{2 + }}$ and two ${\text{C}}{{\text{l}}^ - }$ ions. Therefore one mole of ${\text{MgC}}{{\text{l}}_2}$ dissociates to give one mole of ${\text{M}}{{\text{g}}^{2 + }}$ and two moles of ${\text{C}}{{\text{l}}^ - }$ ions. Its dissociation occurs as follows:

${\text{MgC}}{{\text{l}}_2}\rightleftharpoons {\text{M}}{{\text{g}}^{2 + }}+{\text{2C}{{\text{l}}^ - }$

${\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_3}$ is an ionic compound that is formed by two ${\text{N}}{{\text{a}}^ + }$ and one ${\text{CO}}_3^{2 - }$ ion. Therefore one mole of ${\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_3}$ dissociates to give two moles of ${\text{N}}{{\text{a}}^ + }$ and one mole of ${\text{CO}}_3^{2 - }$ ion. The reaction for dissociation of ${\mathbf{N}}{{\mathbf{a}}_{\mathbf{2}}}{\mathbf{C}}{{\mathbf{O}}_{\mathbf{3}}}$ is,

${\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_3}\to2{\text{N}}{{\text{a}}^ + }+{\text{CO}}_3^{2 - }$

Learn more:

1. Identification of ionic bonding: brainly.com/question/1603987

2. Basis of investigation for the scientists: brainly.com/question/158048

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic and covalent compounds

Keywords: Ionic compound, cation, anion, ions, Na2CO3, Na+, CO32-, dissociation, neutral atom, electrons.