Answer:
148 g H₂SO₄
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Reading a Periodic Table
- Balancing RxN's
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
RxN: Ca(OH)₂ + H₂SO₄ → CaSO₄ + H₂O
Given: 3.01 moles H₂O
<u>Step 2: Balance RxN</u>
Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O
- Need the same amount of O's and H's on both sides
<u>Step 3: Define conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol
<u>Step 4: Stoichiometry</u>
<u />
= 147.625 g H₂SO₄
<u>Step 5: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules.</em>
147.625 g H₂SO₄ ≈ 148 g H₂SO₄
Answer:
0.24 L of oxygen gas will be required to produce 0.160 L of nitrogen gas.
Explanation:
From the reaction, 3 moles of oxygen react with ammonia to produce 2 moles of nitrogen gas
So, 3 moles of 02 = 2 moles of N2
Since I mole of a gas occupies 22.4dm^3 or 22,4 L of the gas
3 * 22,4L of O2 produces 2 * 22.4 L of N2
67.2 L of O2 produces 44.8 L of N2
( 67.2 * 0.160 / 44.8 ) L of O2 will produce 0.160L of N2
10.752/ 44,8 L = 0.24 L of O2 will produce 0.160 L of N2
0.24 L of oxygen gas will be required to produce 0.160 L of nitrogen gas.
Answer: yo yo dog i need points
Explanation:
fr fr
First, look for the know oxidation numbers.
In this case, you should know that SO4 comes from H2SO4. When H2SO4 loses 2 H+, SO4 stays with charge 2-
Given that CuSO4 is neutral, the oxidation number of Cu is 2+: (2+) + (2-) = 0.
Conclusion: the oxidation number of Cu is 2+
Answer: i think it is O2- but not sure...
hope this helps if not sorry
Explanation: