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lyudmila [28]
2 years ago
12

A man with hemophilia (a recessive, sex-linked condition) has a daughter without the condition. She marries a man who does not h

ave hemophilia. What is the probability that their daughter will have hemophilia? Their son? If they have four sons, what is the probability that all will be affected?
Biology
1 answer:
Allisa [31]2 years ago
7 0

Answer:

Since the condition is sex-linked, it must be related to the X chromosome.

Let X^{A} represent the dominant allele and X^{a} the recessive one, the daugther must have a X^{a} chromosome from the father (the only one he could pass) and a X^{A} from the mother, otherwise she wouldn't be female (X^{a}Y) or would have the condition (X^{a}X^{a}).

If the man does not have the condition, he has the dominant allele on the X chromosome, represented as X^{A}Y. You can use Punett squares to represent their cross.

\begin{center}\begin{tabular}{ |c|c|c|c| }\ & X^{a} & X^{A} \\ \ X^{A} & X^{A}X^{a} & X^{A}X^{A} \\ \ Y & X^{a}Y & X^{A}Y \\ \end{tabular}\end{center}

None of the possible daugthers could have the condition, but there is a 50% chance of their son having it (1/2).

In total, since there is a chance of 1/2 for their son to be affected, the probability of having four sons with the condition is 1/2⁴, or 6.25%.

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