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4 years ago

A hydrate of CoCl2 with a mass of 6.00 g is heated strongly. after cooling the mass the anhydrate is 3.27g

Chemistry

2 answers:

Oduvanchick [21]4 years ago

7 0

Answer : The amount of water lost from the hydrate is 2.73 grams.

Explanation :

Let us assume that we are calculating the amount of water lost from the hydrate.

As we are given:

Mass of hydrate of $CoCl_2$ = 6.00 g

Mass of anhydrate = 3.27 g

Mass of water lost = Mass of hydrate of $CoCl_2$ - Mass of anhydrate

Mass of water lost = 6.00g - 3.27g

Mass of water lost = 2.73 g

Hence, the amount of water lost from the hydrate is 2.73 grams.

Brums [2.3K]4 years ago

6 0

We are given with a hydrate with a mass of 6 grams and after heating the mass and cooling afterward, the mass went down to 3.27 grams. The amount of water in the hydrate thus is 6-3.27 g or 2.73 grams.That is equivalent to 45.5 percent by mass water.

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Brass is a substitutional alloy consisting of a solution of copper and zinc. A particular sample of red brass consisting of 79.0

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Explanation:

Solute is the substance which is present in smaller proportion in a mixture and solvent is the substance which is present in larger proportion in a mixture.

We are given:

(m/m) % of Cu = 79 %

This means that 79 g of copper is present in 100 grams of alloy.

(m/m) % of Zn = 21 %

This means that 21 g of zinc is present in 100 grams of alloy.

As, zinc is present in smaller proportion. So, it is solute and copper is the solvent.

Calculating molality of zinc:

To calculate molality of the zinc, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$m_{solute}$ = Given mass of solute (Zinc ) = 21 g

$M_{solute}$ = Molar mass of solute (Zinc) = 65.3 g/mol

$W_{solvent}$ = Mass of solvent (copper) = 79 g

Putting values in above equation, we get:

$\text{Molality of Zinc}=\frac{21\times 1000}{65.3\times 79}\\\\\text{Molality of zinc}=4.07m$

Calculating molarity of zinc:

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = $8740kg/m^3=\frac{8740kg\frac{1000g}{1kg}}{1m^3\times \frac{10^6cm^3}{1m^3}}=\frac{8740g}{1000cm^3}=8.740g/cm^3$

(Conversion factors used are: 1 kg = 1000 g & $1m^3=10^6cm^3$ )

Mass of solution = 100 g

Putting values in above equation, we get:

$8.740g/cm^3=\frac{100.0g}{\text{Volume of zinc}}\\\\\text{Volume of zinc}=11.44cm^3$

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$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molar mass of zinc = 65.3 g/mol

Volume of solution = $11.44cm^3=11.44mL$ (Conversion factor: $1cm^3=1mL$ )

Mass of zinc = 21.0 g

Putting values in above equation, we get:

$\text{Molarity of zinc}=\frac{21\times 1000}{65.3\times 11.44}=28.11M$

Hence, the molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

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For example : sand in a water, soil etc.

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Air is a homogeneous mixture of gases.

Coffee with sugar stirred in is also homogeneous mixture.

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