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Hunter-Best [27]
4 years ago
5

F

Chemistry
1 answer:
Firdavs [7]4 years ago
7 0

Answer:

yes

Explanation:

but actually no

You might be interested in
which atoms attains a stable valence electron configuration by bonding with another atom 1) neon 2) radon 3) helium 4) hyrdogen
Sergeu [11.5K]
Well, when an atom attains a stable valence electron, it means that the outer electrons are complete and so cannot attain any more electrons. For the first shell, it is complete when it has 2 electrons, the second shell is complete when it has 8 electrons, all the other shells also have a particular number when complete. Anyway, i believe the answer is HYDROGEN because when HYDROGEN combines with another atom of HYDROGEN, the outer shell is completed. This is because HYDROGEN has only 1 electron. If the two HYDROGENS, which both have 1 electron combine, they make the electrons 2, which is complete for the first shell, HYDROGEN ends in the first shell. Since the electrons become 2, the shell is at stable valence. In all the other options, this happens;
NEON- It has 10 electrons, 2 in the first shell and 8 in the second. So the the shells are already complete, so it can't bond with any thing, which is completely against the question.
RADON- Radon has 86 electrons.
HELIUM- Helium has 2 electrons, so the shell is already full, and cannot bond, so it goes against the question. The question says BY BONDING.
 So the answer is definitely 4) HYDROGEN
Hope i helped. Have a nice day, by the way, i'm very sure it's hydrogen.

3 0
3 years ago
Question 5 (1 point)
ollegr [7]

Answer:

0.00125 moles H₃X

Solution and Explanation:

In this question we are required to calculate the number of moles of triprotic acid neutralized in the titration.

Volume of NaOH used = final burette reading - initial burette reading

                                      = 39.18 ml - 3.19 ml

                                      = 35.99 ml or 0.03599 L

Step 1: Moles of NaOH used

Number of moles = Molarity × Volume

Molarity of NaOH = 0.1041 M

Moles of NaOH = 0.1041 M × 0.03599 L

                          = 0.00375 mole

Step 2: Balanced equation for the reaction between triprotic acid and NaOH

The balanced equation is;

H₃X(aq) + 3NaOH(aq) → Na₃X(aq) + 3H₂O(l)

Step 3: Moles of the triprotic acid (H₃X used

From the balanced equation;

1 mole of the triprotic acid reacts with 3 moles of NaOH

Therefore; the mole ratio of H₃X to NaOH is 1 : 3.

Therefore;

Moles of Triprotic acid = 0.00375 mole ÷ 3

                                     = 0.00125 moles

Hence, moles of triprotic acid neutralized during the titration is 0.00125 moles.

3 0
4 years ago
Help me out here please???
san4es73 [151]

Answer:

A

Explanation:

5 0
3 years ago
Read 2 more answers
O2 + C3H2 + H2O + CO2<br> Reaction type?
Kobotan [32]

Answer:

Combustion is the reaction type if you meant to put a "=" in between C3H2 and H2O

3 0
4 years ago
A container has the dimensions of 10cm x 80mm x 0.15m. The density of
vesna_86 [32]

Answer:

2.52kg

Explanation:

80mm = 8 cm

0.15m = 15 cm

volume of the container = 10m × 8cm × 15cm

= 1200 cubic centimetres

mass = density × volume

= 2.1 × 1200

= 2520g

2520/ 1000

= 2.52kilograms

8 0
3 years ago
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