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3 years ago

1. A car moves 200m in 4 s. What is the speed of the car? I

Mathematics

2 answers:

algol133 years ago

8 0

Answer:

50m/s

Step-by-step explanation:

Speed = Distance / Time:

Speed = $\frac{200}{4}$ = $50 m/s$

zepelin [54]3 years ago

3 0

Answer:

50mps

Step-by-step explanation:

divide 200 by 4

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Write the inequality that goes with the graph shown.

m_a_m_a [10]

Answer:

—1=<x<-3

Since

X<-3

X>=-1

Not shaded means including.

8 0

2 years ago

Which of the following is equal to 393,500? 0.3935 × 10 -6 39.35 × 10 -4 3.935 × 10 -5 3.935 × 10 5

SCORPION-xisa [38]

Answer:

No answer is equal to 393,500

Step-by-step explanation:

You can try to solve each question.

0.3935 × 10 -6 = -2.065

39.35 × 10 -4 = 389.5

3.935 × 10 -5 = 34.35

3.935 × 10 +5 = 44.35

None of these equal to 393,500

(Maybe I am getting things wrong I am not in a smart mood today)

4 0

3 years ago

How do you do this i am lost

Jet001 [13]

Answer:

The solution is (-2, 4)

Step-by-step explanation:

When finding the solution of system of equations, you need to find where both lines intersect.

In the graph shown, the light purple and dark purple line meet at (-2, 4).

Hope this helps!!

8 0

3 years ago

Find the equation of the line that is perpendicular to y = –4x + 8 and passes though the point (–12, 4). A) y = – 1 4 x + 7 B) y

____ [38]

Answer:

Step-by-step explanation:

perp: 1/4

y - 4 = 1/4(x + 12)

y - 4 = 1/4x + 3

y = 1/4x + 7

answer is C

6 0

3 years ago

Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

laila [671]

Answer:

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$

Now we have everything in order to replace into formula (1):

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

4 0

3 years ago