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marusya05 [52]
3 years ago
7

What type of control would describe training, inspection, and housekeeping?

Engineering
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

Administrative controls,

Explanation:

such as training, inspection, housekeeping and so on can be used to limit exposure.

You might be interested in
he following is true for a Function Generator (select all that apply): Select one or more: a. It produces a variety of patterns
Amanda [17]

Answer:

A,C and E

Explanation:

It should be understood that a function generator can be explained as a piece of electronic test equipment or software which is used in generating different types of electrical waveforms over a wide range of frequencies. It should be noted that some of the examples of waveforms produced by the function generator are the sine wave, square wave, triangular wave and sawtooth shapes.

Therefore, the reason why of picking the options as highlighted above.

4 0
4 years ago
A glass plate is subjected to a tensile stress of 40 MPa. If the specific surface energy is 0.3 J/m2 and the modulus of elastici
Pavlova-9 [17]

Answer:

8.24μm

Explanation:

The theory of brittle fracture was used to solve this problem.

And if you follow through with the attachment made a the subject of the formula

Such that,

a = 2x(69x10⁹)x0.3/pi(40x10⁶)²

= 4.14x10¹⁰/5.024x10¹⁵

= 8.24x10^-06

= 8.24μm

This is the the maximum length of the surface flaw

4 0
3 years ago
A piston-cylinder device contains 1.329 kg of nitrogen gas at 120 kPa and 27 degree C. The gas is now compressed slowly in a pol
Shtirlitz [24]

Answer:-0.4199 J/k

Explanation:

Given data

mass of nitrogen(m)=1.329 Kg

Initial pressure\left ( P_1\right )=120KPa

Initial temperature\left ( T_1\right )=27\degree \approx 300k

Final volume is half of initial

R=particular gas constant

Therefore initial volume of gas is given by

PV=mRT

V=0.986\times 10^{-3}

Using PV^{1.49}=constant

P_{1}V^{1.49}=P_2\left (\frac{V}{2}\right )

P_2=337.066KPa

V_2=0.493\times 10^{-3} m^{3}

and entropy is given by

\Delta s=C_v \ln \left (\frac{P_2}{P_1}\right )+C_p \ln \left (\frac{V_2}{V_1}\right )

Where, C_v=\frac{R}{\gamma-1}=0.6059

C_p=\frac{\gamma R}{\gamma -1}=0.9027

Substituting values we get

\Delta s=0.6059\times\ln \left (\frac{337.066}{120}\right )+0.9027 \ln \left (\frac{1}{2}\right )

\Delta s=-0.4199 J/k

4 0
3 years ago
Compare and contrast an electric vehicle with one powered by a fuel cell.
zmey [24]

Answer:

both technologies offer a cleaner alternative to internal combustion engines, and both use electric motors powered by electrochemical device.

3 0
3 years ago
Just to let you know Christmas is in 10 days&lt;3<br><br> lol
Harrizon [31]

Answer:

yay yay

Explanation:

im so excited i cant wait

7 0
3 years ago
Read 2 more answers
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