When the rope is at an angle of α = 30°, the 1-kg sphere A has a speed v0 = 0.6 m/s. The coefficient of restitution between A an
d the 2-kg wedge B is 0.8 and the length of rope l = 0.9 m. The spring constant has a value of 1500 N/m and θ = 20°. Determine (a) the velocities of A and B immediately after the impact, (b) the maximum deflection of the spring, assuming A does not strike B again before this poin
1 answer:
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Answer:
T = 167 ° C
Explanation:
To solve the question we have the following known variables
Type of surface = plane wall ,
Thermal conductivity k = 25.0 W/m·K,
Thickness L = 0.1 m,
Heat generation rate q' = 0.300 MW/m³,
Heat transfer coefficient hc = 400 W/m² ·K,
Ambient temperature T∞ = 32.0 °C
We are to determine the maximum temperature in the wall
Assumptions for the calculation are as follows
- Negligible heat loss through the insulation
- Steady state system
- One dimensional conduction across the wall
Therefore by the one dimensional conduction equation we have
During steady state
= 0 which gives
From which we have
Considering the boundary condition at x =0 where there is no heat loss
= 0 also at the other end of the plane wall we have
hc (T - T∞) at point x = L
Integrating the equation we have
from which C₁ is evaluated from the first boundary condition thus
0 = from which C₁ = 0
From the second integration we have
From which we can solve for C₂ by substituting the T and the first derivative into the second boundary condition s follows
→ C₂ =
T(x) = and T(x) = T∞ +
∴ Tmax → when x = 0 = T∞ +
Substituting the values we get
T = 167 ° C
Answer:
see explaination
Explanation:
Balanced equation or stoichiometry equation means in a product after reaction there is no unburned carbon compound left or we can say the oxygen is sufficient to combine with all the carbon and hydrogen moleculs to form Carbon-dioxide and water respectively.
The dew point temperature of balanced equation will be 100°c because water vapour bis present in it and it will condense at 100°c at 1 bar pressure while the other products need much lower temperatures to liquify.
See attachment.
