Answer:
411.953 kpa
Explanation:
We have the following assumptions
1. Steady incompressible flow.
2. Burst section water pressure = water main pressure
3. Air and water have negligible friction between them.
Max height = 42 m
Max water density = 277.14k
Density of water
Pwater = 999.8395kg/m
Water gets to 42m because of pressure in the line
P (line) = Pwater * g * h
= 999.8395 x 9.81 x 42
= 411.953Kpa
Answer:
a)
b)
Explanation:
a)
In order to solve this problem, we need to start by remembering how the acceleration is related to the velocity of a particle. We have the following relation:
in other words, the acceleration is defined to be the derivative of the velocity function with respect to time. So let's take our speed function:
u=20-2x
if we take its derivative we get:
du=-2dx
this is the same as writting:
we also know that velocity is defined to be:
so we get that:
a=-2u
when substituting we get that:
a=-2(20-2x)
when expanding we get:
a=-40+4x
and now we can use this equation to find our acceleration at x=3, so:
a=-40+4(3)
a=-40+12
b)
the same applies to this problem with the difference that this will be the rate of change of the temperature per m. So we proceed and take the derivative of the temperature function:
T=200-5x
so the rate of change is
Answer:
HTTP is solving the problem of how to ask for that file. Your computer and that server communicate using a protocol called HTTP.
Answer:
number of stages for the pump is 4
Explanation:
given data
water head Hm = 50 m
flow rate r = 0.1 m³/s
rotating N = 1800 rpm
to find out
optimal number of stages for the pump.
solution
we consider here specific speed does not exceed more than 82
so Ns formula will be
Ns =
here Ns id 82 and N is rotating and r is flow rate
so
82 =
so H = 13.23 m
so
number of stage n is
nH = Hm
n =
n = 3.77 ≈ 4
so number of stages for the pump is 4