Answer: No, we don't have a right triangle
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Explanation:
If a triangle with sides a,b,c makes the equation a^2+b^2 = c^2 true, where c is the longest side, then this triangle is a right triangle. This is the converse of the pythagorean theorem.
Here we have a = 2, b = 5 and c = 7.
So...
a^2+b^2 = c^2
2^2+5^2 = 7^2
4+25 = 49
29 = 49
The last equation is false, so the first equation is false for those a,b,c values. Therefore, we do <u>not</u> have a right triangle.
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In contrast, consider the classic 3-4-5 right triangle
a = 3, b = 4 and c = 5 would make a^2+b^2 = c^2 true because 3^2+4^2 = 5^2 is a true equation (both sides lead to 25).
S > less than or equal to 130
d < greater than or equal to $500
here is your answer mate.
in triangle ABC
angle ABC + angleBAC + angleACB = 180 Degrees. (angle sum property of triangle)
90 + 58 + angle ACB = 180 degree.
148 + angle ACB = 180 degree.
angle ACB = 180 - 148
angle ACB = 32 degree
the angle of elevation is 32 degrees
6 minivans are needed to take (i think I'm real bad at math)
Answer:
for m∠SRQ x = 3
for m∠QRP x = 5
Step-by-step explanation:
1. 6x +2. 6 is being multiplied by a number so to find that number we do teh opposite
6x/2 = 3
drop the x then u have x = 3
2. 2x+10. 2 is being muliplied by a number so to find that number we do teh opposite
10/2x = 5
drop the x then u have x = 5
