How would u solve this liner system?

1 answer:

8 0

We can solve it by substitution: y = - 3 x - 1.
So the 2nd equation becomes:
4 x + 3 * ( - 3 x - 1 ) = 2
4 x - 9 x - 3 = 2
- 5 x = 2 + 3
- 5 x = 5
x = 5 : ( - 5 ) = - 1
y = - 3 * ( - 1 ) - 1 = 3 - 1 = 2
Answer: x = - 1, y = 2.

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How do you do this. Please give a full answer and explain why.

OverLord2011 [107]

Law of Exponent

$\displaystyle \large{ {a}^{ - n} = \frac{1}{ {a}^{n} } }$

Compare the terms.

$\displaystyle \large{ {a}^{ - n} = {( - 2)}^{ - 3} }$

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ {( - 2)}^{ 3} } }$

Exponent Def. (For cubic)

$\displaystyle \large{ {a}^{3} = a \times a \times a }$

Factor (-2)^3 out.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}$

(-2) • (-2) = 4 | Negative × Negative = Positive.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{4 \times ( - 2)}}$

4 • (-2) = -8 | Negative Multiply Positive = Negative.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ - 8}}$

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

$\displaystyle \large \boxed{ {( - 2)}^{ - 3} = - \frac{1}{ 8}}$

The answer is - 1 / 8

3 0

3 years ago

Am i right brainliest going to first correct answer

Firdavs [7]

The solution to the inequality is -20.8 > p (imagine the symbol is the symbol for at least)

5 0

3 years ago

Read 2 more answers

2.8 ÷ -0.004. Please show work.

Alexeev081 [22]

Answer:

Step-by-step explanation:

$\frac{2.8}{-0.004}\\\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}\\\\=-\frac{2.8}{0.004}\\\\\mathrm{Divide\:the\:numbers:}\:\frac{2.8}{0.004}=700\\\\=-700$