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3 years ago

Draw and label Trapezoid ZOID with ZO II ID and IO= ZD

Mathematics

2 answers:

Lyrx [107]3 years ago

8 0

Answer:no

Step-by-step explanation:

miv72 [106K]3 years ago

6 0

Check the picture below.

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Identify the graph of y=2^x+3

Mila [183]

could you show me a picture so maybe i can answer it please

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3 years ago

What is the unit price for the cans of lemonade at each of the stores. The store prices are 3 for 9$

11Alexandr11 [23.1K]

9$ for three cans then 9/3= 3 $ per can

3 0

3 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago

4. The price of a sweater is $5 less than the price of the shirt. If four sweaters and

Anon25 [30]

Answer:

Form an equation:

let x be the price of a shirt

Then, the price of a sweater would be x - 5

So you would have:

4(x - 5) + 3x = 200

simplify

4x - 20 + 3x = 200

7x - 20 = 200

add 20 to both sides

7x = 220

divide both sides by 7

x = about 31.43

That means the cost of the sweater would be 31.43 - 5 = 26.43

4 0

3 years ago

Mrs Hong had some milk. She used of it to bake some waffles and

Sergio [31]

Answer:

Mrs. Hong originally had 900 ml of milk

Explanation:

The complete question is in the attached image

Assume that the amount of milk Mrs. Hong originally had was x ml

We are given that:

1- She used $\frac{1}{6}$ of it to bake the waffles, therefore:

Amount used in baking waffles = $\frac{1}{6}x$ ml

2- She used 300 ml to bake a pie

3- Amount left is half the original amount, therefore:

Amount left = $\frac{1}{2}x$ ml

We know that:

Total amount = amount used in waffles + amount used in pie + amount left

Substitute with the givens and solve for x:

Total amount = amount used in waffles + amount used in pie + amount left

$x = \frac{1}{6}x + 300 + \frac{1}{2}x\\ \\x-\frac{1}{6}x-\frac{1}{2}x = 300\\ \\\frac{1}{3}x = 300\\ \\x = 300*3 = 900 ml$

This means that:

She originally had 900 ml of milk

Hope this helps :)

7 0

3 years ago

Draw and label __ __ Trapezoid ZOID with ZO II ID and IO= ZD

Draw and label Trapezoid ZOID with ZO II ID and IO= ZD