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AlekseyPX
3 years ago
11

Draw and label __ __ Trapezoid ZOID with ZO II ID and IO= ZD

Mathematics
2 answers:
Lyrx [107]3 years ago
8 0

Answer:no

Step-by-step explanation:

miv72 [106K]3 years ago
6 0
Check the picture below.

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Can someone help me?
juin [17]

Answer:

5/12

Step-by-step explanation:

8 0
3 years ago
Exactly 120 tickets were sold for a concert. The tickets cost $12 each for adults, $10 each for seniors, and $6 each for childre
Gemiola [76]
A=adult tickets
c=chlderenticekts
s=sinior tickets

a=c

a+c+s=120
2a+s=120

total made is 1100
12a+6c+10s=1100
sub
a=c
12a+6a+10s=1100
add
18a+10s=1100

multiply first equation by -9 and add to other equation

-18a-9s=-1080
18a+10s=1100 +
0a+s=20

s=20
20 senior tickets were sold

answer is B
5 0
3 years ago
PLEASE HELP
Fantom [35]

Multiply the price per month by the number of months (m) and add that to the price of the phone.

The equation would be y = 530 + 44.99m

8 0
3 years ago
Read 2 more answers
What is the Gradient and y axis of 5x-2y=10
VikaD [51]

Convert to slope-intercept form.

5x - 2y = 10

2y = 5x - 10

y = (5/2)x - 5

So the slope is 5/2 and y-intercept is at (0, -5).

8 0
4 years ago
The third term of a sequence is 120. The fifth term is 76.8. Write an explicit rule representing this geometric sequence.
juin [17]
The nth term of the geometric sequence is:
an=ar^(n-1)
where 
a=first term
r=common ratio
n=nth term
from the question:
120=ar(3-1)
120=ar^2
a=120/(r^2)....i
also:
76.8=ar^(5-1)
76.8=ar^4
a=76.8/r^4.....i
thus from i and ii
120/r^2=76.8/r^4
from above we can have:
120=76.8/r²
120r²=76.8
r²=76.8/120
r²=0.64
r=√0.64
r=0.8
hence:
a=120/(0.64)=187.5
therefore the formula for the series will be:
an=187.5r^0.8
4 0
3 years ago
Read 2 more answers
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