Answer:
∠1 = 90°
∠2 = 66°
∠3 = 24°
∠4 = 24°
Step-by-step explanation:
Usually the diagonals of a rhombus bisect each other at right angles.
Thus; ∠1 = 90°
Since they bisect at right angles, then;
∠R1S = 90°
Now, sum of angles in a triangle is 180°
Thus;
66° + 90° + ∠4 = 180°
156 + ∠4 = 180
∠4 = 180 - 156
∠4 = 24°
Now, also in rhombus, diagonals bisect opposite angles.
Thus; ∠4 = ∠3
Thus, ∠3 = 24°
Similarly, the diagonal from R to T bisects both angles into 2 equal parts.
Thus; ∠2 = 66°
Step-by-step explanation:
(2x³y^-4)^-2 = 1/(4x⁶y^‐8) = y⁸/(4x⁶)
1/(8x⁵y^-7) = y⁷/(8x⁵)
4x^-9y⁴ = 4y⁴/x⁹
so, the whole expression is then
y⁸/(4x⁶) × y⁷/(8x⁵) × 4y⁴/x⁹
4y¹⁹/(32x²⁰) = y¹⁹/(8x²⁰)
so, D is the correct answer.
Answer:
2)
collect like terms
move the constant to the right hand side and change its sign.
Subtract the numbers
Divide both sides of the equation by 8
Answer:
1, -1 , -3 ,3
Step-by-step explanation:
Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
