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Tanzania [10]
3 years ago
9

Simplify. (x3)5 5x3 x15 x2 x8

Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

x^8

Step-by-step explanation:

when multiplying two things with exponents you must add the exponents(:

maks197457 [2]3 years ago
3 0
You just combine like terms so it'll be 5x^43
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Write 55 as a product of its prime factors
Roman55 [17]

Answer:

55 = 5 × 11

Step-by-step explanation:

The only prime factors of 55 are 5 and 11, thus

55 = 5 × 11

4 0
3 years ago
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What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8
mariarad [96]
To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ 
(2) \ ln \  b^{a} = a*ln \ b \\
(3) \ ln \ a + ln \ b = ln \ (ab) \\
(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

The given equation is :
ln \  e^{ln \ x} + ln \  e^{ln \  x^{2}} = 2 \ ln \ 8
ln \ x * ln \ e + ln \  x^{2} * ln \ e = 2 \ ln \ 8  ⇒⇒⇒⇒ rule (2)
ln \ x + ln \  x^{2} = ln \  8^{2}  ⇒⇒⇒⇒ rule (1) and rule (2)

ln \ ( x*  x^{2} ) = ln \ 64          ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

x^{3} = 64 =  4^{3}
∴ x = 4


So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4


5 0
3 years ago
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What is the fourth term of the expansion of the binomial (2x + 5)5? A. 10x2 B. 5,000x2 C. 1,250x3 D. 2,000x3
zhannawk [14.2K]

Answer:

B would be the answer for this question.


Step-by-step explanation:


7 0
4 years ago
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NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)
olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level       PA (men)      PA (Women)

Sedentary              1.00                1.00

    Low                    1.11                1.12

  Active                   1.25                1.27

Very Active              1.48                1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

        = 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0
3 years ago
Robert had two of rope he cut off eight inches how many inches does he have left
pishuonlain [190]
16 inches. 24 - 8 = 16.
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3 years ago
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