Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
the correct answer would be d.
Step-by-step explanation:
These lines should be straight line, since they have no slope.
Word Form: Seven hundred ten thousand two hundred.
1.25 also bc they are parallel
Answer:
See below ↓↓↓
Step-by-step explanation:
<u>Subquestion #1</u>
- These angles form a linear pair
- They are supplementary, and add up to 180°
- 2x + 48 = 180
- 2x = 132
- <u>x = 66</u>
<u></u>
<u>Subquestion #2</u>
- These angles are complementary, and add up to 90°
- 35 + 4x + 7 = 90
- 4x + 42 = 90
- 4x = 48
- <u>x = 12</u>
<u></u>
<u>Subquestion #3</u>
- As in #1, they are a linear pair, and are supplementary
- 3x + 54 = 180
- 3x = 126
- <u>x = 42</u>