Number 1 is multiply it by the cube then multiply it by the number
Two positive integers have gcd (a, b) = 15 and lcm (a, b) = 90. Those two numbers are 15 and 90 or 30 and 45.
Suppose we have 2 positive integers, a and b, then:
gcd (a, b) = the greatest common divisor = common prime factors of a and b
lcm (a, b) = the least common multiple = multiplication of the greatest common prime factors of a and b
In the given problem:
gcd (a, b) = 15
prime factorization of 15:
15 = 3 x 5
Hence,
a = 3 x 5 x ....
b = 3 x 5 x ....
lcm (a, b) = 90
prime factorization of 90:
90 = 3 x 5 x 2 x 3
Therefore the possible pairs of a and b are:
Combination 1:
a = 3 x 5 = 15
b = 3 x 5 x 2 x 3 = 90
Combination 2:
a = 3 x 5 x 2 = 30
b = 3 x 5 x 3 = 35
We can conclude the two integers are 15 and 90 or 30 and 45.
Learn more about gcd here:
brainly.com/question/16969353
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Answer:
1.79553
Step-by-step explanation:
Step 1: Write expression
log₁₀(√(69.5² - 30.5²))
Step 2: Evaluate square root
log(√(4830.25 - 930.25))
log(√3900)
log(62.45)
Step 3: Find log
log₁₀ (or log)
log(62.45) = 1.79553
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To use the table method. we find values that are easily evaluated by log₁₀
log₁₀(10) = 1
log₁₀(50) = 1.69897
log₁₀(100) = 2
So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.
Answer:
Step-by-step explanation:
This a test?
