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bezimeni [28]
3 years ago
6

the table below shows relative frequencies of players outcomes for two teams one player will be randomly selected to be interviw

ed​

Mathematics
1 answer:
Maslowich3 years ago
4 0

Answer:

Tationia Rolon

Step-by-step explanation:

I think it will be letter b because the the amount that game lost is greater than the total of wins

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Find AC. PLSSS HELP BRAINLIEST....
MrRissso [65]

Answer:

5.3

Step-by-step explanation:

Cos(68) = adjacent/hypotenuse

Cos(68) = 2/AC

AC = 2/cos(68)

AC = 5.3389343253

AC = 5.3

4 0
3 years ago
Read 2 more answers
Put the steps in correct order to prove that if x is irrational, then 1/x is irrational using contraposition.
SOVA2 [1]

Answer:

The correct order is:

a

c

d

b

Step-by-step explanation:

First, let's write 1/x in a convenient way for us:

a) Substitute 1/x = p/q, to obtain x = 1/(1/x) = 1/(p/q) = q/p.

Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:

c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.

Now we know that we can write x as a quotient of two integers, we need to imply that, then the next one is:

d) Observe that x is the quotient of two integers with the denominator nonzero.

And that is the definition of rational, then we end with:

b) Hence x is rational.

Which is what we wanted to get.

5 0
2 years ago
Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0
3 years ago
Jose has scored 562 points on his math test so far this this semester. To get an A for the semester, he must score at least 650
I am Lyosha [343]

Answer:

562 + x ≥ 650

x ≥ 88

Step-by-step explanation:

He has 562 points.  He needs x points to get an A.  He must get at least 60 points to get an A.

562 + x ≥ 650

To solve this, we subtract 562 from each side

562-562 + x ≥ 650-562

x  ≥ 650-562

x ≥ 88

6 0
2 years ago
A car travelled at 50 km/hr for 3 hours How far did the car travel?
jasenka [17]

Answer:

25km

Step-by-step explanation:

50 km = x km

1 hr        3 hrs

From there, you cross-multiply and solve for x.

(50 km)*(3 hrs) = (x km)*(1 hr)

x km = (50)*(3)/(1) = 150km

Now, your other question can be answered the exact same way. 30 minutes is the same as 1/2 of an hour, so just put 0.5hrs in where the 3hrs was in the previous problem. So to show you how it works once more, here are your calculations:

50 km = x km

1 hr        0.5 hrs

(50 km)*(0.5 hrs) = (x km)*(1 hr)

x km = (50)*(0.5)/(1) = 25km

I hope that helps!

6 0
3 years ago
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