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vovangra [49]
3 years ago
5

Ten students in Mrs porth's class bring muffins

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0
Whats the question what do u want me to solve 
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What is the solution of two thirds x=12
joja [24]
Hi there!

To solve this problem, we need to simplify. 

2/3x = 12

To isolate x, we should multiply both sides of the equation by the reciprocal of 2/3 to make x equal to a value:

Reciprocal of 2/3 = 3/2

x = 12 * 3/2
x = 18 

Hope this helps!
8 0
3 years ago
This is my my second to <br>last one, thanks for helping me
icang [17]

9514 1404 393

Answer:

  • $9
  • Option 4

Step-by-step explanation:

The equations need to match the problem statements. If we let C and S represent the costs of Cherry and Sweet potato pies, respectively, then the revenue from each sale can be expressed as an equation.

  1 cherry and 7 sweet potato for $114   ⇒   C +7S = 114

  14 sweet potato and 11 cherry for $309   ⇒   11C +14S = 309

Note that we have used C and S in the second equation in the same order as they appeared in the first equation, even though the problem statement has that order reversed. This facilitates solving the equations using elimination or Cramer's rule.

These equations match Option 4.

__

The cost of a cherry pie can be found by eliminating S from the equations. We can do that by subtracting twice the first equation from the second:

  (11C +14S) -2(C +7S) = (309) -2(114)

  9C = 81 . . . . . simplify

  C = 9 . . . . . . . divide by 9

The cost of each cherry pie is $9.

3 0
4 years ago
22. What is the product of (8-37(3 + 21)
Roman55 [17]

Answer:

I believe its -800, but i'm not sure.

7 0
3 years ago
A box contains 17 marbles, 13 blue marbles, and 23 white marbles. What is the part-whole ratio of red marbles in the box.
sergij07 [2.7K]
Since the ratio is part-Whole, first you need to find the whole. If you add all of the marble colors together (17+13+23) you get the total marbles (53) in the box. The ratio of red marbles to the total would be 17 to 53.
6 0
3 years ago
Brad runs a lap every 5 minutes and Ty runs a lap every 4 minutes. If they started at the same time, when will they get to the b
olganol [36]
20 minutes. On brads 4th run and Ty’s 5th run they will be at the beginning at the same time.
5 0
4 years ago
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