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2 years ago

How does the heat content of the reaction change in the process of photosynthesis when a glucose molecule is formed?

1 answer:

4 0

In the process of photosynthesis, when a glucose molecule is formed, THE HEAT CONTENT OF THE REACTION INCREASES, THUS, THE VALUE OF Q IS POSITIVE.

There are two types of chemical reaction, these are exothermic and endothermic reaction. Exothermic reactions are those reactions that gives off heat when they are occurring while endothermic reactions are those reactions that absorb heat from their environment during the course of reaction. Photosynthesis is an endothermic reactions; it absorbs energy from the environment when it is occurring, thus, the heat content of the product is always more than that of the reactants. The heat content of compounds are represented by letter q. For photosynthesis, q is positive, because there is an increase in the heat content of the product [glucose] formed.

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3 years ago

In a coffe cup calorimeter, 50.0mL of 0.100M of AgNO3 and 50mL of 0.100M HCl are mixed to yield the following reaction:

Jet001 [13]

Answer:

The enthalpy change of the reaction is -66.88 kJ/mol.

Explanation:

Mass of the solution = m = 100 g

Heat capacity of the solution = c = 4.18 J/g°C

Initial temperature of the solutions before mixing = $T_1=22.60^oC$

Final temperature of the solution after mixing = $T_2=23.40^oC$

Heat gained by the solution due to heat released by reaction between HCl and silver nitrate = Q

$Q=m\times c\times (T_2-T_1)$

$Q=100 g\times 4.18 J/g^oC\times (23.40^oC-22.60^oC)=334.4 J$

Heat released due to reaction = Q' =-Q = -334.4 J

Moles of silver nitrate = n

Molarity of silver nitrate solution = 0.100 M

Volume of the silver nitrate solution = 50.0 mL = 0.050 L ( 1 mL = 0.001 L)

$Moles =Molarity\times Volume (L)$

$n=0.100 M\times 0.050 L=0.005 mol$

Enthalpy change of the reaction = $\Delta H$

$=\Delta H=\frac{-334.4 J}{0.005 mol}=-66,880 J/mol=-66.88 kJ/mol$

1 J = 0.001 kJ

The enthalpy change of the reaction is -66.88 kJ/mol.

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2 years ago

Calculate the grams of ethane present in a sample containing 0.8286 moles if the molar mass of ethane is 30.067 g/mol.

BlackZzzverrR [31]

N = m/M

Where,

n = number of moles

m = mass of substance

M = molar mass of substance

0.8286 = m / 30.067

Multiply both sides by 30.067

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2 years ago