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3 years ago

Pls help if you only know the correct answer! Thanks! :)

Chemistry

1 answer:

serious [3.7K]3 years ago

5 0

Answer:

i think itd be an exothermic reaction

Explanation:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise.

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How many particles are in on mole?

shusha [124]

The answer is 1023 particles

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3 years ago

How many molecules of sulfur trioxide are in 78.0 grams?

zalisa [80]

Answer:

b) 5.87 E23 molecules

Explanation:

∴ mm SO3 = 80.066 g/mol

⇒ molecules SO3 = (78.0 g)(mol/80.066 g)(6.022 E23 molec/mol)

⇒ molec SO3 = 5.866 E23 molecules SO3

5 0

3 years ago

The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c

crimeas [40]

Answer : The rate constant at 785.0 K is, $1.45\times 10^{-2}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $600.0K$ = $6.1\times 10^{-8}s^{-1}$

$K_2$ = rate constant at $785.0K$ = ?

$Ea$ = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $600.0K$

$T_2$ = final temperature = $785.0K$

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]$

$K_2=1.45\times 10^{-2}s^{-1}$

Therefore, the rate constant at 785.0 K is, $1.45\times 10^{-2}s^{-1}$

7 0

3 years ago

What makes salt an ionic compound?

Bond [772]

Salt consists of positive sodium ions and negative chloride ions

6 0

3 years ago

A sample of helium gas has a pressure of 1.20 atm at 22°c. at what celsius temperature will the helium reach a pressure of 2.00

sukhopar [10]

Gay-Lussac's law gives the relationship between pressure and temperature of a gas.
it states that for a fixed amount of gas of constant volume pressure is directly proportional to temperature.
P/T = k
where P - pressure, T - temperature and k - constant
$\frac{P1}{T1} = \frac{P2}{T2}$
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
temperature should be in the kelvin scale,
T1 = 22 °C + 273 = 295 K
substituting the values in the equation
$\frac{1.20atm}{295 K} = \frac{2.00 atm}{T}$
T = 492 K
new temperature - 492 - 273 = 219 °C

5 0

3 years ago