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Nat2105 [25]
3 years ago
12

PLEASE HELP ASAP WILL GIVE BRAINIEST!!! 25PTS!!!!! GEOMETRY!!!!!

Mathematics
1 answer:
adoni [48]3 years ago
6 0
Its pretty simple really, you have to find b to begin

p.s. you don't need to worry about 8c+5d, that's just there to confuse you.


these to angles : (12b+6)° and (2b+6)° if added together have to equal 180°

so you add the two equations together


(12b+6)+(2b+6)=180

you then solve for b:


add like terms together
12b+2b and 6+6

you then are left with

14b+12=180

then you solve for x

14b+12=180
-12 -12
14b=168
÷14 ÷14
b=12


now that you have B you
plug that in to the original equation opposite of (4a)

(2b+6)

you plug in the number you got for b

2(12)+6
24+6
=30

so now you now the angle opposite of (4a)
and opposite angles have to equal each other so
4a=30

solve for a and that's your answer

4a=30
÷4. ÷4
a=7.5










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The opposite of -48 is positive 48, Written as just 48.

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1. Diego runs a 10 kilometer race and keeps track of his speed. What was diegos speed at the kilometer mark in the race?
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Step-by-step explanation:

In the graph below, Diego's speed at various points during his 10 kilometer race is shown on the y axis while the distance is shown on the x axis.

Looking at the 1km mark on the x axis, Diego's speed on the y-axis is at 10km/ hr and this was the speed he started the race with. After the kilometer mark however, his speed changed and went on to increase to 11km/ hr by the second kilometer mark.

5 0
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A salesperson earns a commission of $459 for selling $2700 in merchandise find the commission rate. Write the answer as a percen
kogti [31]
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4 0
3 years ago
What is the value of 30-2(7+2)-1
Firdavs [7]

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6 0
3 years ago
PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0
2 years ago
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