Answer:
15.999 amu
Explanation:
15.999 amu
Explanation:
From the question given above, the following data were:
Isotope A:
Mass of A 15.995 amu
Abundance (A%) = 99.759%
Isotope B:
Mass of B = 16.995 amu
Abundance (B%) = 0.037%
Isotope C:
Mass of C = 17.999 amu
Abundance (C%) = 0.204%
Atomic mass of Oxygen =.?
The atomic mass of oxygen can be calculated by using the following formula:
Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
Atomic mass = [(15.995 × 99.759)/100] + [(16.995 × 0.037)/100] + [(17.999 × 0.204)/100]
Atomic mass = 15.956 + 0.006 + 0.037
Atomic mass = 15.999 amu
Therefore, the atomic mass of oxygen is 15.999 amu
The correct answer is 3) 2CO2(g) ⇄ 2CO(g) + O2(g)
this is the correct one because it is a decomposition reaction and all the number of atoms is equal on both sides.
there are 2 C atoms on both sides.
and 4 O atoms on both sides.
and 1) the atoms numbers are equal on both sides but not correct as it not a
correct number as it has 1/2 O2.
and 2) CO2(g) ⇆ CO(g) + O2
the number of O atoms is not equal on both sides of the equation.
we have 2 O atoms on the left side and 3 O atoms on the right side.
so, this not a balanced equation.
4) also not correct 2CO(g) + O2 ⇆ 2CO2
as it is not a decomposition reaction and the 2CO & O2 are as reactants not products.
so the correct answer is 3) 2CO2(g) ⇆ 2CO(g) + O2(g)
Answer:
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Explanation:
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Answer:
B) A piece of metal in water and produces spark and gas