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andreyandreev [35.5K]
4 years ago
12

Which of the following is a sign a chemical reaction has occurred?

Chemistry
1 answer:
Salsk061 [2.6K]4 years ago
4 0

Answer:

B) A piece of metal in water and produces spark and gas

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What occurred during the Triassic Period
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What is the molecule polarity of SiCl4????
mars1129 [50]

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Silicon Tetrachloride:Explanation:

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7 0
4 years ago
The 1H NMR signal for bromoform (CHBr3) appears at 2065 Hz when recorded on a 300−MHz NMR spectrometer. If the spectrum was reco
VladimirAG [237]

Answer:

The chemical shift (δ) for CHBr₃ proton = <u>6.88 ppm</u>

Explanation:

In NMR spectroscopy, Chemical shift (δ) is expressed in parts per million (ppm) and is given by the equation:

\delta (ppm)= \frac{Observed\: frequency, \nu (Hz)}{Frequency\: of\: Spectrometer, \nu^{'} (MHz)}\times 10^{6}                     ....equation (1)

Given: Observed frequency: ν₁ = 2065 Hz,

Spectrometer frequency: ν'₁ = 300 MHz, ν'₂ = 200 MHz

To calculate the chemical shift (δ) for the given CHBr₃ proton, we use the equation (1)

\delta = \frac{\nu_{1} (Hz)}{\nu_{1}^{'} (MHz)}\times 10^{6} = \frac{2065 Hz}{300 \times 10^{6} Hz}\times 10^{6} = 6.88 ppm

Since in NMR spectroscopy, chemical shift is a <em>field independent scaling</em>. Thus the value of the chemical shift of a given proton, such as CHBr₃ proton, is <u><em>independent of the magnetic field strength of the spectrometer.</em></u>

<u>So the value of chemical shift of a given proton remains same when measured with a 300 MHz and 200 MHz NMR spectrometer.</u>

<u>Therefore, the chemical shift (δ) for CHBr₃ proton = 6.88 ppm</u>

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3 years ago
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