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Andre45 [30]
3 years ago
10

Which best describes what forms in nuclear fusion?

Chemistry
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:

A) two smaller, more stable nuclei

Explanation:

i had got the question wrong from the other "answer" and it showed that A was the correct one

frez [133]3 years ago
5 0

Answer. One larger, more stable nucleus.

Explanation:

Nuclear Fusion: When two small atomic nuclei fuse together to form one larger atomic nucleus. During this process a lot of energy is released which means product formed will be stable.

For example: Deuterium-Deuterium fusion leads to the formation of helium isotope.

_{1}^{2}\textrm{H}+_{1}^{2}\textrm{H}\rightarrow_{2}^{3}\textrm{He}+_{0}^{1}\textrm{n}+3.27Mev


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3 years ago
What information does a solubility table give?
guajiro [1.7K]

Answer:

Option D - It tells which compounds will dissolve in water.

Explanation:

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4 0
2 years ago
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A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
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Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

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<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

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7 0
3 years ago
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Gnoma [55]
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7 0
3 years ago
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