At time t, there are 216t + 18 bacteria of type A and 362t + 8 bacteria of type B organisms in a sample. When will the number of each type of bacteria be equal? Answers voices are:
A) t=38
B) t=-38
C) t=6
D) t=9/4
1 answer:
We must set the two expressions to be equal:
216t + 18 = 362t + 8
Subtract 216t from both sides:
18 = 146t + 8
Subtract 8 from both sides:
10=146t
Divide both sides by 146:
t = 10/146 = 5/73
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