64/3=x/1
easy, just divide
64/3=21 and 1/3 calls per hour
Answer:
H0 : μ = 8.5
H1 : μ > 8.5
1 sample t test ;
Test statistic = 2.53
Pvalue = 0.994
No, we fail to reject the Null ;
There is no significant evidence to support the Claim that the mean running time of light bulb is greater Tha last year.
Step-by-step explanation:
H0 : μ = 8.5
H1 : μ > 8.5
Test statistic :
(xbar - μ) ÷ (s/sqrt(n))
(8.7 - 8.5) ÷ (0.5 / sqrt40)
Test statistic = 2.53
The Pvalue :
P(Z < 2.53) = 0.9943
Pvalue = 0.994
Decison region :
Reject H0 ; if Pvalue < α
0.9943 > 0.05 ; We fail to reject the Null
The right answer is -2/3
please see the attached picture for full solution
Hope it helps..
Good luck on your assignment..
Answer:
Therefore 80 ceperies will he need to sell this month.
Step-by-step explanation:
Average: Average is the ratio of sum of all numbers to the total number present in the data.
Given that Herbert has sold 99, 37, 86 and 73 copeirs in the last 4 months.
Let he need to sell x copeirs in this month.
According to the problem,

⇒ 99+37+86+73+x= 75×5
⇒295 + x= 375
⇒x = 375 - 295
⇒ x= 80
Therefore 80 ceperies will he need to sell this month.
Answer:
y=4/3x - 5
Step-by-step explanation: