Answer:
radius 2
Step-by-step explanation:
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab,
is equal to
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus,
. Since a and b were generic elements of H, then H/G is abelian.
in 1st figure
2:1=(x+2):2
2/1=(x+2)/2
4=x+2
x=2.
Similarly in the 2nd figure
8:5=(8+3):(5+x)
8/5 = 11/ (5+x)
8(5+x) =55
40+8x=55
8x=15
x=15/8
x=1.875
Bottom = 2x5 = 10ft
Middle = 2x6 ( 4+2) = 12
Top 4x2= 8
10ft+12ft+8ft= 30ft squared
Left Side Triangle: x = 142°
Top Middle Triangle: x = 136°
Bottom Middle Triangle: x = 26°
Right Side Triangle: x = 54°