Ft = tangential force = mg sin θ / 2
<h3>Further explanation </h3>The force acting on a system with static equilibrium is 0
(forces acting as translational motion only, not including rotational forces)
For objects undergoing rotation, the equilibrium must be met
The force acting on the rod is the tension in the rope (T)and the weight of the rod
(w)
Because the sum of torques must be zero (objects in equilibrium) then : (use point A as the pivot point)
(Ft = tangential force)
Στ = 0
Ft. L - w sin θ. 1/2 L = 0
Ft = T cos θ, and w = mg, such that
T cos θ. L - mg sin θ. 1/2 L = 0
T cos θ. L = mg sin θ. 1/2 L
T cos θ = mg sin θ. 1/2
law of motion
displacement of a skateboarder
The distance of the elevator
Answer: 96 m/s
Explanation:
Given information
Acceleration of rocket = 24 m/s2
Distance travelled by rocket = 192 meters.
To be calculated
Velocity of rocket at 192 meters = ?
Using 2nd equation of motion, the difference of square of final and initial velocity is equal to the 2 times the product of acceleration and distance.
v2 – u2 = 2as
v2 – 0 = 2 * 24 * 192 (intial velocity is 0, so u = 0)
v2 = 9216
v =
v = 96 m/s