In an electrical circuit, a voltage difference:

A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?

Dafna11 [192]

Answer:

15m/s²

Explanation:

Given parameters:

Initial velocity = 10m/s

Final velocity = 40m/s

Time taken = 2s

Unknown:

Average acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time;

Acceleration = $\frac{Final velocity - Initial velocity }{time}$

Acceleration = $\frac{40 - 10}{2}$ = 15m/s²

6 0

3 years ago

What inertia is present in streched rybber

MrRissso [65]

<h2>You input potential (stored) energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this kind of potential energy is specifically called elastic potential energy.</h2><h2>Hope it helps..</h2>

4 0

3 years ago

Which example best describes mechanical advantage?. A) A fixed pulley changes the direction that you pull. B) Greasing a surface

Jet001 [13]

Needed to be pointed out that mechanical advantage is when the distance traveled is traded for force applied

from the following options, the one that is considered a mechanical advantage is : C. a longer lever helps lift more weight

hope this helps

4 0

3 years ago

Read 2 more answers

Charlie Brown kicks a football at 24.5 m/s at 35.0. What is the maximum height of the ball?

lozanna [386]

Answer:

d = 10.076 m

Explanation:

We need to obtain the velocity of the ball in the y direction

Vy = 24.5m/s * sin(35) = 14.053 m/s

To obtain the distance, we use the formula

vf^2 = v0^2 -2*g*d

but vf = 0

d = -vo^2/2g

d = (14.053)^2/2*(9.8) = 10.076 m

5 0

3 years ago

Two point charges of equal magnitude q are held a distance d apart. Consider only points on the line passing through both charge

NemiM [27]

let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.

the mathematical formula for potential is $V=\frac{1}{4\pi\epsilon} \frac{q}{d}$

for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as- $E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}$

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero between the two charges,but we can find the points situated on the axial line but outside of charges where the electric field is zero.

now let the two charges of same nature.let these are positively charged.

here we can not find a point between two charges and on the line joining two charges where the potential is zero.

but at the mid point of the line joining two charges the filed is zero.

5 0

4 years ago