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Hatshy [7]
3 years ago
8

The quotient of 300 and the quality of x times 2

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0
300 over x to the power of 2
asambeis [7]3 years ago
4 0
\frac{300}{ x^{2}} 
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Find the value of c that makes each trinomial a perfect square.<br> x^2-13x+c
vova2212 [387]

Answer:

169/4

Step-by-step explanation:

x² - 13x + c

x² -2(x)(13/2) +(13/2)²

(13/2)² = 169/4 or 42 ¼

8 0
3 years ago
How many permutations are there of the letters in the words (a) TRISKAIDEKAPHOBIA (fear of the number 13)? (b) FLOCCINAUCINIHILI
zubka84 [21]

Answer: Hello!

Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)

We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.

The total number of permutations is the product of the number of options that you have for each letter, this is:

17*16*15*14*....*3*2*1 = 17! = 3.6e+14

(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is

30! = 2.65e+32

(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.

then P = 47! = 2.59e+59

(d) DERMATOGLYPHICS: here are 18 letters, then:

p = 18! = 6.4e+15

6 0
3 years ago
1 basic algebreh im slow hlp me 2
Ivahew [28]

Answer:

it is D

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in
Elanso [62]

Answer:

0 < t < \frac{5}{3}

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = \frac{20}{12}

t = \frac{5}{3} days

Therefore, there are two intervals in which the given function is defined

(0, \frac{5}{3}) and (\frac{5}{3}, ∞)

For the interval (0, \frac{5}{3}),

p'(1) = 20 - 12(1) = 20

For the interval (\frac{5}{3}, ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, \frac{5}{3}) indicates that the function is increasing.

0 < t < \frac{5}{3}

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0
3 years ago
How do you solve the problem 6-3x=-2x
jolli1 [7]
6-3x=2x

In order to solve these, you first want to get all the variables on one side. So, you add 3x to both sides.

6=x

The answer is x=6

Hope this helps!
3 0
2 years ago
Read 2 more answers
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