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ratelena [41]
3 years ago
13

A 1 kg ball is dropped from the top of a cliff and falls with a constant acceleration due to gravity (9.8 m/s2). Assume that eff

ects of air resistance can be ignored.a.) By how much has the ball's gravitational potential energy changed after it has fallen
Physics
1 answer:
Volgvan3 years ago
6 0

Answer:

Gravitational potential Energy change of the ball after, 10m= 98J

Explanation:

A 1 kg ball is dropped from the top of a cliff and falls with a constant acceleration due to gravity (9.8 m/s2). Assume that effects of air resistance can be ignored. a.) By how much has the ball's gravitational potential energy changed after it has fallen by 10 m

Gravitational Potential Energy: This is the energy a body posses by virtue of it's position in a gravitational field. It is measured in Joules.

Gravitational potential Energy = Mass(m) × acceleration due to gravity (g) × Height(h) = mgh

Where m = 1kg, g = 9.8 m/s², h =10 m

∴ Gravitational potential Energy change of the ball after, 10m = 1  ×  9.8  ×  10 = 98 J

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<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

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