Question

A conducting coil of 1850 turns is connected to agalvanometer, and the total resistance of the circuit is 45.0 ohm.The area of each turn is 4.70 X 10-4 m2. Thiscoil is moved from a region where the magnetic field is zero into aregion where it is nonzero, the normal to the coil being parallelto the magnetic field. The amount of charge that is induced to flowaround the circuit is measured to be 8.87 X 10-3 C. Findthe magnitude of the magnetic field. (Such a device canbe used to measure the magnetic field strength and is called aflux meter).

Answer 1

Answer:

0.459 Tesla

Explanation:

Faraday's law:

$Emf = -N\frac{\delta\phi}{\delta t}$

Φ= NAB

V =   N Δ (BA) /Δt      

the change in BA

was:    BA =  0   because initially B was zero.

V=IR

   IR =   N B A /Δt

   q / Δt ×R   =      N B A / Δt

Or:    B =   q R / NA = 8.87 x 10^-3 × 45.0 / 1850×4.7 x 10^-4 =

          = 0.459 Tesla