Answer: 1) 17.65 * 10^-12 C/V; 2) 0.68 V
Explanation: In order to calculate the capacitance of one cylinder capacitor we have to use the following expression:
where and b are the inner and outer radius of teh cylinder, respectively. L is length of the cylinder.
Finally we also kwn that C=Q/ΔV
then we have
ΔV =Q/C
ΔV = 12 * 10^-12/17.65*10^-12= 0.68V
Answer:
A) ≥ 325Kpa
B) ( 265 < Pe < 325 ) Kpa
C) (94 < Pe < 265 )Kpa
D) Pe < 94 Kpa
Explanation:
Given data :
A large Tank : Pressures are at 400kPa and 450 K
Throat area = 4cm^2 , exit area = 5cm^2
<u>a) Determine the range of back pressures that the flow will be entirely subsonic</u>
The range of flow of back pressures that will make the flow entirely subsonic
will be ≥ 325Kpa
attached below is the detailed solution
<u>B) Have a shock wave</u>
The range of back pressures for there to be shock wave inside the nozzle
= ( 265 < Pe < 325 ) Kpa
attached below is a detailed solution
C) Have oblique shocks outside the exit
= (94 < Pe < 265 )Kpa
D) Have supersonic expansion waves outside the exit
= Pe < 94 Kpa
