Answer:
Explanation:
First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=
Reaction equation:
Zn + 2HCl → ZnCl₂ + H₂
One mole of gas occupies 22.4 L at STP
Moles of H₂ = 112/22.4
= 5 moles
The theoretical amount of Zn needed is 5 mol
The actual amount = 5/0.85
= 5.88 moles
mass = moles x Mr
mass = 5.88 x 65
mass = 382.2 g
The answer is D.
A biomolecule with a hydroxyl (--oh) functional group is
given the polar chemical property since organic molecules with an OH group are
polar.
A part of a larger molecule is made up by a functional
group. The hydroxyl group (-OH) that characterizes alcohols, an oxygen with a
hydrogen attached, is an example of it. This group can be found on any number
of different molecules.
Functional groups have characteristic chemistries, just
as elements have unique properties., although perhaps not identically,
to an -OH on another molecule. Although perhaps not
identically to an -OH on another molecule, an -OH group on one molecule will tend to react similarly.
Answer:
plants
animals
Explanation:
From the given choices only plants and animals are biotic in nature. Biotic factors are factors that can be attributed to living organisms.
The other choices such as water, light and minerals are abiotic. They are do not originate from living organisms.
Both biotic and abiotic factors are present within the ecosystem. In fact, they influence the ecosystem to a very large extent.
Together, these factors shapes the ecosystem.
The balanced equation for the reaction is as follows
8SO₂ + 16H₂S ---> 3S₈ + 16H₂O
stoichiometry of SO₂ to H₂S is 8:16
we have been given 77.0 g of each reactant
the reactants react according to molar ratio in other words according to the stoichiometry
8 mol of SO₂ reacts with 16 mol of H₂S
number of SO₂ moles present - 77.0 g / 64 g/mol = 1.20 mol
number of H₂S moles present - 77.0 g / 34 g/mol = 2.26 mol
we need to find the limiting reactant
limiting reactant is fully used up in the reaction
amount of product formed depends on amount of limiting reactant present
if SO₂ is the limiting reactant
if 8 mol of SO₂ reacts with 16 mol of H₂S
then 1.20 mol of SO₂ reacts with - 16/8 x 1.20 mol = 2.40 mol of H₂S
but only 2.26 mol of H₂S are present
which means H₂S is the limiting reactant
then amount of S₈ formed depends on H₂S present
stoichiometry of H₂S to S₈ is 16:3
16 mol of H₂S forms 3 mol of S₈
then 2.26 mol of H₂S forms - 3/16 x 2.26 = 0.424 mol
mass of S₈ formed - 0.424 mol x 256 g/mol = 108.5 g
108.5 g of S₈ is formed