0.0000297 kg would be the answer to ur question :)
Answer:
A)
<u>4, 7, 4, 6</u>
B)
<u>12 moles</u>
Explanation:

__↑______↑
8.00 mol | 14.00 mol
________________

You can turn this into a system of variables which are solvable.
To do this, create variables for the coefficients of each compound in the reaction respectively.

Because to be balanced, the count of atoms in each element of the compound correspond to the coefficient of the variable in that compound so that the count of the left (reactant) side is set equal to the right (product) side.
a corresponds to the coefficient of the first compound, b corresponds to the coefficient of the second compound, c corresponds to the coefficient of the third compound, and d corresponds to the coefficient of the fourth compound.
(Reactant = Product)
Reactant: 1a [N] Product: 1c.
Reactant: 3a [H] Product: 2d.
Reactant: 2b [O] Product: 2c + 1d.
Thus the system is:
1a = 1c
3a = 2d
2b = 2c + 1d.
Then just use the substitution methods to solve.
The misture can be separated by filtration.
Answer:
1. London dispersion
Explanation:
Sulphur trioxide ( SO₃ ) -
The chemical compound SO₃ is planar in structure , the only intermolecular forces shown by SO₃ is the London forces .
dipole - dipole is not observed in this compound , as it is not possible to generate poles between the sulfur and oxygen atom due to very less difference in the electronegativity .
Hydrogen bonding is also not observed , because there is not hydrogen atom .
Hence , only London forces are observed in SO₃ .