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rusak2 [61]
2 years ago
11

A sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density? ​

Physics
1 answer:
Hoochie [10]2 years ago
3 0

Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

Ro = m/V

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ]

And the mass m = 4 [gramm] = 0.004 [kg]

Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}]

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3 years ago
When a space shuttle was launched, the astronauts onboard experienced an acceleration of 32.0 m/s2 . If one of the astronauts ha
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Answer:

F = 1280 N

Explanation:

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Acceleration experienced by a space shuttle, a = 32 m/s²

Mass of the astronauts, m = 40 kg

We need to find the force experienced by the astronaut.

We know that the net force is equal to the product of acceleration and its mass. So,

F = ma

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F = 1280 N

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8 0
3 years ago
A mass of 1.03 kilograms is placed on a horizontal frictionless surface against an uncompressed spring with spring constant 861.
Lelechka [254]

Answer:

5.522 m

Explanation:

Data provided:

Mass, m = 1.03 kg

spring constant, k = 861.1 N/m

Distance by which the spring is compressed, x = 0.36

Thus,

the energy stored in the spring = \frac{1}{2}kx^2

on substituting the values, we get

the energy stored in the spring =  \frac{1}{2}\times861.1\times0.36^2

now,

by the conservation of energy, we have

Potential energy gained by the mass =  Energy gained by the spring

or

mgh = \frac{1}{2}\times861.1\times0.36^2

where,

g is the acceleration due to the gravity

h is the maximum height reached by the mass before falling

on substituting the values in the above relation, we get

1.03 × 9.81 × h = \frac{1}{2}\times861.1\times0.36^2

or

h = 5.522 m

8 0
3 years ago
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