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rusak2 [61]
2 years ago
11

A sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density? ​

Physics
1 answer:
Hoochie [10]2 years ago
3 0

Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

Ro = m/V

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ]

And the mass m = 4 [gramm] = 0.004 [kg]

Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}]

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Answer:

I don't really know

Explanation:

I really wanted to help you, but then I realized i didnt know how to

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2 years ago
A wood block, after being given a starting push, slides down a ramp at a constant speed. what is the angle of the ramp above hor
Stells [14]

The solution for the problem is:

Constant speed means Fnet = 0. 
Let m = mass of wood block and Θ = angle of ramp; then if µk = 0.35 …

The computation would be:


Fnet = 0 = mg (sin Θ) - (µk) (mg) (cos Θ) 
mg (sin Θ) = µk (mg) (cos Θ) 
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5 0
3 years ago
At resonance, what is impedance of a series RLC circuit? less than R It depends on many other considerations, such as the values
denis23 [38]

Answer:

at resonance impedence is equal to resistance and quality factor is dependent on R L AND C all

Explanation:

we know that for series RLC circuit impedance is given by

Z=\sqrt{R^2+\left ( X_L-X_C \}right )^2

but we know that at resonance X_L=X_C  

putting  X_L=X_C in impedance formula , impedance will become

Z=R so at resonance impedance of series RLC is equal to resistance only

now quality factor of series resonance is given by

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3 0
3 years ago
Help immediately! Answer I need help.
garri49 [273]

Answer:

0.80 m

Explanation:

elastic potential energy formula

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4 0
2 years ago
g An airplane is flying through a thundercloud at a height of 1500 m. (This is a very dangerous thing to do because of updrafts,
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Answer:

523269.9\ \text{N/m}

Explanation:

q = Charge

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q_1=25\ \text{C}

r_1=3000\ \text{m}

q_2=40\ \text{C}

r_2=850\ \text{m}

The electric field is given by

E=E_1+E_1\\\Rightarrow E=k(\dfrac{q_1}{r_1^2}+\dfrac{q_2}{r_2^2})\\\Rightarrow E=9\times 10^9\times (\dfrac{25}{3000^2}+\dfrac{40}{850^2})\\\Rightarrow E=523269.9\ \text{N/m}

The electric field at the aircraft is 523269.9\ \text{N/m}

4 0
3 years ago
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