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lapo4ka [179]
2 years ago
9

you want to describe the harmonic motion of a swing. you find out that it takes 2 seconds for the swing to complete one cycle. w

hat is the swings period and frequency?
Physics
1 answer:
7nadin3 [17]2 years ago
4 0
If it takes the swing 2 seconds to complete one cycle, then
that's the period of its motion ... 2 seconds.

The frequency is the reciprocal of the period ... 1/2 Hz.
('Hz' means 'per second'.)
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A baseball of mass m = 0.31 kg is spun vertically on a massless string of length L = 0.51m. The string can only support a tensio
natulia [17]

Given data:

* The mass of the baseball is 0.31 kg.

* The length of the string is 0.51 m.

* The maximum tension in the string is 7.5 N.

Solution:

The centripetal force acting on the ball at the top of the loop is,

\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}

For the maximum velocity of the ball at the top of the vertical circular motion,

v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}

where g is the acceleration due to gravity,

Substituting the known values,

\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}

Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.

8 0
1 year ago
How fast is a 90kg man running if his kinetic energy is 720 J?
zheka24 [161]
Answer:
4 m/s
Explanation:
KE=1/2mv^2
720=1/2(90)
720=45v^2
divide by 45
16= v^2
over the square root
4=v
v= 4m/s
6 0
2 years ago
The acceleration of an object is due to the net force on the object and the object's
Marat540 [252]

Answer:

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8 0
3 years ago
An electron (m=9.11x10^-31 kg) moves in a circle whose radius is 2.00x10^-2 m. If the force acting on the electron is 4.60x10^-1
harina [27]

Answer:

The speed of the electron is v = 1.01 x 10¹⁵ m/s

Explanation:

Given data,

The mass of the electron, m = 9.11 x 10⁻³¹ kg

The radius of the circle, r = 2.00 x 10⁻² m

The force acting on electron, F = 4.60 x 10⁻¹⁴ N

The speed of the electron, v = ?

The centripetal force of the electron is given by

                                          F = mv² / r

∴                                         v² = Fr/m

                                           v =√(Fr/m)

Substituting the given values in the above equation,

                                          v =√( 4.60 x 10⁻¹⁴ x 2.00 x 10⁻² / 9.11 x 10⁻³¹ )

                                           v = 1.01 x 10¹⁵ m/s

Hence, the speed of the electron is v = 1.01 x 10¹⁵ m/s

4 0
2 years ago
William Tell shoots an apple from his son's head. The speed of the 100-g arrow just before it strikes the apple is 29.4 m/s, and
Cerrena [4.2K]

To solve this problem it is necessary to apply the kinematic equations of motion (vertical in this case) as well as the momentum conservation equations.

For conservation of the moment we have to

m_1v_1 = (m_1+m_2)v_f

Where

m_{1,2} = Mass of each object

v_1 = Initial velocity of arrow

v_f= Final Velocity

Time in flight for arrow-apple combination is

t= \sqrt{\frac{2h}{g}}

Where,

h = Max height

g = Gravitational acceleration

Now after the impact arrow-apple combination have horizontal velocity V and it is

V= \frac{x}{t}

From the previous definition we have that the value of time would be,

V = \frac{x}{\sqrt{\frac{2h}{g}}}

Assuming the son's height is 1.85m, then we should

V = \frac{8.5}{\sqrt{\frac{2(1.85)}{9.8}}}

V = 13.83m/s

Applying again the conservation equation we can obtain the value of the apple mass as:

m_2 = m_1(\frac{V_1}{ V_f} - 1)

m_2 = 0.125(\frac{29.4}{13.83} - 1)

m_2 =0.1407kg

m_2 = 140.7 g

Therefore the mass of the apple was 140.7g

6 0
3 years ago
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