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2 years ago

Which of the following is a zone found in the open ocean

Physics

2 answers:

Svetlanka [38]2 years ago

5 0

What are your answer choices?

horrorfan [7]2 years ago

5 0

The answer to this question is D.

The neritic zone (option a) is a shallow area of ocean (about 200m in depth) which is essentially the area where the ocean interacts with the coast, although in very rare cases this can be further out to sea dependent on the oceanic plate.

The surface zone (option b) is, as the name suggests, where the ocean and the air meet and therefore not exclusive to the "open ocean" as specified in the question.

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A point charge is at the origin. With this point charge as the source point, what is the unit vector r^ in the direction of (a)

KiRa [710]

Answer:

a. $\hat{r} =- \hat{j}$
b. $\hat{r} = \ \frac{1}{\sqrt{2}} \ \hat{i} + \ \frac{1}{\sqrt{2}} \ \hat{j}$
c. $\hat{r} = \ -0.3871 \ \hat{i} + \ 0.91501\ \hat{j}$

Explanation:

Using Coulomb's Law we know that the electric field E at point $\vec{r}$ is:

$\vec{E(\vec{r})} = k_e \frac{q}{d^2} \frac{\vec{r}-\vec{r'}}{d}$

where $k_e$ is the Coulomb's Constant, q is the source charge, d is the distance between point and position of the source point charge, and $\vec{r}'$ is the position of the source point charge.

Taking all this in consideration, the unit vector clearly is:

$\hat{r} =\frac{\vec{r}-\vec{r'}}{d}$

For our problem, $\vec{r'} = (0,0)$ , as the charge is located at the origin.

$\hat{r} =\frac{\vec{r}}{d}$

and d will be the magnitude of $\vec{r}$

Now, we can take the values for each point.

$\vec{r}= (0,-1.35 \ m)$

and, the magnitude of the vector is

$|\vec{r}| = \sqrt{r_x^2 + r_y^2}$

$|\vec{r}| = \sqrt{(0 \ m)^2 + (-1.35 \ m )^2}$

$|\vec{r}| =1.35 \ m$

So, the unit vector is:

$\hat{r} =\frac{(0,-1.35 \ m)}{1.35 \ m}$

$\hat{r} =(0,-1,0)$

$\hat{r} =- \hat{j}$

$\vec{r}= (12 \ cm,12 \ cm)$

and, the magnitude of the vector is

$|\vec{r}| = \sqrt{r_x^2 + r_y^2}$

$|\vec{r}| = \sqrt{(12 \ cm)^2 + (12 \ cm )^2}$

$|\vec{r}| = \sqrt{2} \ 12 \ cm$

So, the unit vector is:

$\hat{r} =\frac{(12 \ cm,12 \ cm)}{\sqrt{2} \ 12 \ cm}$

$\hat{r} =(\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}},0)$

$\hat{r} = \ \frac{1}{\sqrt{2}} \ \hat{i} + \ \frac{1}{\sqrt{2}} \ \hat{j}$

$\vec{r}= (-1.10 \ m, 2.60 \ m)$

and, the magnitude of the vector is

$|\vec{r}| = \sqrt{r_x^2 + r_y^2}$

$|\vec{r}| = \sqrt{(-1.10 \ m)^2 + (2.60 \ m)^2}$

$|\vec{r}| = 2.8415 \ m$

So, the unit vector is:

$\hat{r} =\frac{ (-1.10 \ m, 2.60 \ m)}{2.8415 \ m}$

$\hat{r} =(-0.3871 ,0.91501)$

$\hat{r} = \ -0.3871 \ \hat{i} + \ 0.91501\ \hat{j}$

3 0

3 years ago

2. An overseas jet requires 6 hours to fly 9700 km. What is the jet's speed?

Debora [2.8K]

Answer:

Most commercial aircraft typically fly at around 460-575 mph, or 740-930 km/h, according to Flight Deck Friend. But private jet speed can vary depending on a variety of factors, such as the weight onboard and the weather conditions.

4 0

2 years ago

Technician a says that some passenger vehicles use more than one evaporator. technician b says that some passenger vehicles use

dybincka [34]

<span>Tech A is correct. An evaporator is part of the heat exchange system in a vehicle. Sometimes vehicles will have more than one evaporator, each located in different areas of the vehicle. A condenser is part of the air conditioner system, and only one is normally required.</span>

3 0

2 years ago

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

irinina [24]

Answer:

Coil 2 have 235 loops

Explanation:

Given

The number of loops in coil 1 is n ₁= 159

The emf induced in coil 1 is ε ₁ = 2.78 V

The emf induced in coil 2 is ε ₂ = 4.11 V

Let