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madam [21]
3 years ago
8

A cylindrical capacitor is made of two thin-walled concentric cylinders. The inner cylinder has radius 8 mm , and the outer one

a radius 11 mm . The common length of the cylinders is 152 m . What is the potential energy stored in this capacitor when a potential difference 8 V is applied between the inner and outer cylinder? (k =1/4∗π∗ϵ0=8.99×109N⋅m2/C2) A cylindrical capacitor is made of two thin-walled concentric cylinders. The inner cylinder has radius 8 , and the outer one a radius 11 . The common length of the cylinders is 152 . What is the potential energy stored in this capacitor when a potential difference 8 is applied between the inner and outer cylinder? ( =) 8.5×10−7 J 7.5×10−6 J 2.0×10−7 J 1.4×10−7 J 9.6×10−7 J
Physics
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

So the answer is the first one

E = 8.5 x 10 ⁻⁷ J

Explanation:

Given:

r₁ = 8 mm , r₂ = 11 mm , h = 152 m

ε₀ = 8.85 x 10⁻¹² N * m² / C²

C = Q / V

C = 2π * h * ε₀ / ln ( r₂ / r₁ )

C = [ 2π * 152 m * 8.85 x 10⁻¹² N * m² / C² ]  / [ ln ( 11 mm / 8mm ) ]

C = 2.654 x 10⁻⁸ F

C = 26.54 nF

Now to determine the energy Emf

E = ¹/₂ * C * V²

E = ¹/₂ * 26.54 nF * 8²V

E = 8.5 x 10 ⁻⁷ J

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Answer:

 L  = 1.15 m

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We substitute in the first equation

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The distance is measured from the center point of maximum, which coincides with the center of the slit, in this case the distance is the total width of the central maximum, so the distance (y) measured from the center is

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         y = 0.575 10⁻² m

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Let's calculate

     L = 115 10⁻⁶  0.575 10⁻² / 575 10⁻⁹

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